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larisa86 [58]
4 years ago
6

Which graph would help solve the equation5log(x+3)=5?

Mathematics
1 answer:
Nady [450]4 years ago
4 0
Method 1:
By graphing, we can find the graph of y = 5log(x + 3) and y = 5 to see where they intersect.

Method 2:
Alternatively, by subtracting 5 from both sides, we can find where the graph 5log(x + 3) - 5 hits the x-axis. In essence, we are finding when y hits 0 and thus, finding where it hits the x-axis.

Method 3:
We can also just solve this algebraically. When we don't have any superscripts, we take the assumption that we're working in base 10.

Divide both sides by 5:
log(x + 3) = 1

Take the inverse of log(x + 3) to both sides:
10^{log_{10}(x + 3)} = 10^{1}
x + 3 = 10
x = 7

Hence, we know that at x = 7, 5log(7 + 3) = 5.

The graphs of Method 1 is pictured first, and the graph of Method 2 is pictured on the right.

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Which is the approximate measure of angle Y? Use the law of sines to find the answer.
vitfil [10]
Siny/2.7=sin63/2.8

siny=2.7sin63/2.8

y=arcsin((2.7sin63)/2.8)

y≈59.23°  (to nearest one-hundredth of a degree)
8 0
3 years ago
Read 2 more answers
A caterpillar crawling in a straight line across a coordinate plane starts at point (-3,
Irina18 [472]

9514 1404 393

Answer:

  15

Step-by-step explanation:

In vector form, the equation of point p on the line can be written as ...

  p = (-3, -4) +t(25 -(-3), 38 -(-4)) . . . . . for some scalar t

  p = (-3, -4) +t(28, 42)

  p = (-3, -4) +14t(2, 3)

where t takes on any value between 0 and 1.

If we let t = n/14 for some integer 0 ≤ n ≤ 14, then the coordinates of point p will be integers.

There are 15 values that n can have in the allowed range.

The caterpillar touches 15 points with integer coordinates.

7 0
3 years ago
A random sample of 20 purchases showed the amounts in the table (in $). The mean is $49.57 and the standard deviation is $20.28.
son4ous [18]

Answer:

The 98​% confidence interval for the mean purchases of all​ customers is ($37.40, $61.74).

Step-by-step explanation:

We have that to find our \alpha level, that is the subtraction of 1 by the confidence interval divided by 2. So:

\alpha = \frac{1-0.98}{2} = 0.01

Now, we have to find z in the Ztable as such z has a pvalue of 1-\alpha.

So it is z with a pvalue of 1-0.01 = 0.99, so z = 2.325

Now, find M as such

M = z*\frac{\sigma}{\sqrt{n}}

In which \sigma is the standard deviation of the population and n is the size of the sample.

M = 2.325*\frac{20.28}{\sqrt{20}} = 12.17

The lower end of the interval is the mean subtracted by M. So it is 49.57 - 12.17 = $37.40.

The upper end of the interval is the mean added to M. So it is 49.57 + 12.17 = $61.74.

The 98​% confidence interval for the mean purchases of all​ customers is ($37.40, $61.74).

3 0
3 years ago
Find the linear function with the following properties. <br><br> f(0)=−9 Slope of f=−8
Ratling [72]

Answer:

  • f(x) = -8x - 9

Step-by-step explanation:

<h3>Given </h3>

<u>Function f, with </u>

  • f(0) = -9
  • Slope of f = -8
<h3>To find</h3>
  • Linear function
<h3>Solution</h3>

<u>Slope-intercept formula</u>

  • f(x) = mx + b
  • f(0) = -9 means y-intercept b = -9, and the slope is m = - 8

<u>So the function is</u>

  • f(x) = -8x - 9
6 0
3 years ago
Someone i need help i cant expand these expressions
vovangra [49]

Answer: The answer is 5x+6

Step-by-step explanation:

1/3(9x+16+2)+2x

= 1/3(9x)+1/3(16)+1/3(2)+2x

=3x/1+16/3+2/3+2x/1

=3x/1+2x/1+16/3+2/3

Take the L.C.M

=3x+2x/1+16+2/3

=5x/1+18/3

=5x+6

4 0
3 years ago
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