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LuckyWell [14K]
4 years ago
13

Sam is 27 years old. His age is 6 years greater than 3 times Brandon's age. Which method

Mathematics
1 answer:
Vanyuwa [196]4 years ago
5 0

Answer:

b

Step-by-step explanation:

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The function, B (x), models the estimated tuition cost where x is the number
zepelin [54]

The expression that completes the function b(x)​ is b(x) = 33741 * (1.028)^x

<h3>How to determine the expression of b(x)?</h3>

The given parameters are:

Initial value, a = 33741  

Rate, r = 2.8%

The cost of tuition each year since 2015 is represented as

B(x) = a * (1 + r)^x

This gives

B(x) = 33741 * (1 + 2.8%)^x

Evaluate

b(x) = 33741 * (1.028)^x

Hence, the expression that completes the function b(x)​ is b(x) = 33741 * (1.028)^x

Read more about exponential functions at:

brainly.com/question/12636638

#SPJ1

<u>Complete question</u>

A study estimates that the cost of tuition at a university will increase by 2.8% each year. The cost of tuition at the University in 2015 was $33,741 the function b(x) , models the estimated tuition cost , where x is the number of years since 2015.

Find the expression that completes the function b(x)​

4 0
2 years ago
Plzzz helpppp !!! Given m || n, find the value
sweet-ann [11.9K]

Answer:

169 degrees

Step-by-step explanation:

I hope this helps you out!

4 0
3 years ago
Read 2 more answers
Simplify<br> 7(x+3)<br> I am in 7th grade
Marina86 [1]
7(x+3)
= 7x+ 7*3 (distributive property)
= 7x+ 21.

The final answer is 7x+21~
5 0
4 years ago
Read 2 more answers
143+ [(96 + 8) 5] – 42.
Tresset [83]

Answer:

621

Explanation:

143 + (96 + 8)(5) − 42

(96 + 8)(5)

= 520

143 + 520 - 42

= 663

663 - 42

= 621

7 0
3 years ago
How many ways can eight letters be arranged into groups of five where order matters and the first two letters are already chosen
fenix001 [56]

Answer:

120

Step-by-step explanation:

Since we're dealing with a problem where the order matters and the first two letters are already chosen we need to subtract the number of letters and the number of available slots per group.

We use the permutation formula to find the answer, but before that let's check values.

n = 8

k = 5

Now since there are two letters already chosen we have to deduct two from both the value of n and k.

n = 6

k = 3

Now we can use the permutation formula:

_{n}P_{k}=\dfrac{n!}{(n-k)!}

_{6}P_{3}=\dfrac{6!}{6-3)!}

_{6}P_{3}=\dfrac{6!}{3!}

_{6}P_{3}=\dfrac{6*5*4*3*2*1}{3*2*1}

The 3*2*1 cancels out and leaves us with:

_{6}P_{3}=6*5*4

_{6}P_{3}=120

So there are 120 possible ways to arrange eight letters into groups of five where order matters and the first two letters are already chosen.

6 0
3 years ago
Read 2 more answers
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