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Natalka [10]
2 years ago
10

What is the image of (-3,4)

Mathematics
1 answer:
UkoKoshka [18]2 years ago
4 0

Answer:

(2, 3)

Step-by-step explanation:

Since the problem says to add 5 to x, and subtract from y, you can do x = -3 + 5 and y = 4 - 1 to get (2, 3)

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8=8p+13−3p please help ​
Elenna [48]

Answer:

-1=p

Step-by-step explanation:

8=8p+13-3p

8-13=8p-3p

-5=5p

-5÷5=5p÷5

-1=p

8 0
3 years ago
The square of 7/8 is
Charra [1.4K]

Answer:

7/8 squared = 49/56

Square root = 0.330718914.....

Hope that helps!

Step-by-step explanation:

4 0
2 years ago
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Elsies math class has 11 female students and 10 male students. Write the ratio of female students to total number of students in
Art [367]

Answer:

Step-by-step explanation:

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3 0
2 years ago
What is 89.99 divided by 30%
kirill115 [55]

Answer:

if you are dividing 299.96 If you are multiplying 26.99

Step-by-step explanation:

If you are dividing: Factor the numerator and denominator and cancel the common factors.

If you are multiplying: Simplify the expression.

6 0
3 years ago
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A bridge in the shape of an arch connects two cities separated by a river. The two ends of the bridge are located at (–7, –13) a
sdas [7]

Answer:

y=-\dfrac{13}{49}x^2

Step-by-step explanation:

The shape of an arch corresponds to a parabola.

the general equation for a parabola is:

y=ax^2+bx+c

we're given three coordinates: (-7,-13),(7,-13) and (0,0)

so we can plug these values in the general equation to make 3 separate equations:

(x,y) = (-7,-13)

-13=a(-7)^2+b(-7)+c

49a-7b+c=-13

(x,y) = (7,-13)

-13=a(7)^2+b(7)+c

49a+7b+c=-13

(x,y) = (0,0)

0=a(0)^2+b(7)+c

c=0

so we have three equations. and we can solve them simultaneously to find the values of a,b, and c.

we've already found c = 0, let's use substitute it to other equations.

49a-7b+c=-13\quad\Rightarrow\quad49a-7b=-13

49a+7b+c=-13\quad\Rightarrow\quad49a+7b=-13

we can solve these two equation using the elimination method, by simply adding the two equations

\quad\quad49a-7b=-13\\+\quad49a+7b=-13

------------------------------

\quad\quad 98a=-26

\quad\quad a=-\dfrac{13}{49}

Now we can plug this value of a in any of the two equations.

49a-7b=-13

49\left(-\dfrac{13}{49}\right)-7b=-13

-13-7b=-13

-7b=0

b=0

We have the values of a,b, and c. We can plug them in the general equation to find the equation of the arch.

y=\left(-\dfrac{13}{49}\right)x^2+0x+0

y=-\dfrac{13}{49}x^2

49y=-13x^2

This our equation of the arch!

5 0
2 years ago
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