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Agata [3.3K]
3 years ago
8

Please answer!! Will mark Brainliest!!

Mathematics
1 answer:
forsale [732]3 years ago
8 0

Answer:

Is it a multiple choice question

Step-by-step explanation:

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A function is relationship where a member of the Domain maps to one and only one member of the Range.

To prove a relationship is a function, a VERTICAL LINE TEST may be performed.  If a vertical line cuts the graph of a relationship only once then it is a function if not, then it is not.

View the image attached for the test.   

The answer is option A

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3 years ago
Ethan's taxable income is $87,525. Use this tax schedule to calculate the total amount he owes in taxes.
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Answer: $18,617.75 is the answer

$87,525-$77,100=$10,425 (the amount over $77,100)

$10,425 x .28=$2,919 (the 28% taxed amount over $77,100)

$2,919+$15,698.75 (the already taxed amount in the chart)=$18,617.75

Step-by-step explanation:

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3 years ago
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Gideon is painting all sides of a square pyramid-shaped decoration at the top of his fence post. A net of the decoration is show
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Gideon is painting all sides thus we find the overall area of the square pyramid given in the picture. A square pyramid is a polyhedron that consists of a square and 4 triangles. To solve the area that Gideon will have to paint, we can calculate the area of the square and the area of the triangles then add these two values of area. We proceed as follows:
Area of the square = s^2 where s is the measure of the side
Area of the square = 4^2 = 16 in^2

Area of the triangle= 1/2 bh where b is the base of the triangle and h is height of the triangle
Area of the triangle = 1/2 (4) (5) = 10 in^2
We multiply the area of the triangle to four in order to obtain the total area of the triangles.
Total area of the triangles = 4 x 10 = 40 in^2

We then add the two areas,
Total Area = 16 + 40 = 56 in^2

Thus the total area that Gideon will have to paint for one square pyramid is 56 in^2.
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3 years ago
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A perpendicular bisector, , is drawn through point C on .
Liula [17]

Answer:

The x-intercept of CD is B(18/5,0). The point C(32,-71) lies on the line CD.

Step-by-step explanation:

the x-intercept of CD is[ A(3,0) B(18/5,0) C(9,0) D(45/2,0) ] . Point [ A(-52,117) B(-20,57) C(32,-71) D(-54,-128) ] lies on CD.

Given :

CD is perpendicular bisector of AB.

The coordinates of point A are (-3, 2) and the coordinates of point B are (7, 6).

C is the midpoint of AB.

C=(\frac{x_1+x_2}{2},\frac{y_1+y_2}{2})=(\frac{7-3}{2},\frac{2+6}{2})=(2,4)

The coordinates of C are (2,4).

Line AB has a slope of:m_1=\frac{y_2-y_1}{x_2-x_1}=\frac{6-2}{7-(-3)}=\frac{4}{10}=\frac{2}{5}

The product of slopes of two perpendicular lines is -1. Since the line CD is perpendicular to AB, therefore the slope of CD : m_2=-\frac{5}{2}

The point slope form of a line is given by:

y-y_1=m(x-x_1)

The slope of line CD is -\frac{5}{2} and the line passing through the point (2,4), the equation of line CD can be written as:

y-4=-\frac{5}{2}(x-2)\\y=-\frac{5}{2}x+5+4\\y=-\frac{5}{2}x+9       .... (1)

The equation of CD is y=-\frac{5}{2}x+9

In order to find the x-intercept, put y=0.

0=-\frac{5}{2}x+9\\\frac{5}{2}x=9\\x=\frac{18}{5}

Therefore the x-intercept of CD is B(18/5,0).

Put x=-52 in eq(1).

y=-\frac{5}{2}(-52)+9=139

Put x=-20 in eq(1).

y=-\frac{5}{2}(-20)+9=59

Put x=32 in eq(1)

y=-\frac{5}{2}(32)+9=-71

Put x=-54 in eq1).

y=-\frac{5}{2}(-54)+9=144

Thus, only point (32,-71) satisfies the equation of CD. Therefore the point C(32,-71) lies on the line CD.

8 0
3 years ago
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