what side lengths should be used to model a rectangle with an area of x^2+3x-10 square units? x-5 and x+2 x and x+3 x+3 and x-10

Mathematics

2 answers:

enot [183]3 years ago

8 0

Answer:

None of the 3 available answers models the given rectangle

I believe (x+5)(x-2) would be equal though.

Step-by-step explanation:

(x-5)(x+2) = x²+2x-5x-10

simplify:

x²-3x-10 ≠ x²+3x-10

(x)(x+3) = x²+3x

simplify:

x²-3x ≠ x²+3x-10

(x+3)(x-10) = x²-10x+3x-30

simplify:

x²-7x-30 ≠ x²+3x-10

klemol [59]3 years ago

5 0

Answer:

Answer: x-2 and x+5 side lengths should be used to model a rectangle.

Step-by-step explanation:

can u make me brainiest pls

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Select all the correct answers. Which vectors are unit vectors?

Ahat [919]

Answer:

Step-by-step explanation:

$(-\frac{1}{3} \sqrt{\frac{7}{2} } )^2+(\frac{1}{3} \sqrt{\frac{13}{2} } )^2\\=\frac{1}{9} (\frac{7}{2} +\frac{13}{2} )\\=\frac{1}{9} (\frac{7+13}{2} )\\=\frac{1}{9} \times10\\=\frac{10}{9} \neq 1$

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$(\frac{1}{2} \sqrt{\frac{5}{3} } )^2+(-\frac{1}{2} \sqrt{\frac{7}{3} } )^2\\=\frac{1}{4} (\frac{5}{3} +\frac{7}{3} )\\=\frac{1}{4} (\frac{5+7}{3} )\\=\frac{1}{4} (\frac{12}{3} )\\=\frac{1}{4} (4)\\=1$