Let <em>q</em> be the number of quarts of pure antifreeze that needs to be added to get the desired solution.
8 quarts of 40% solution contains 0.40 × 8 = 3.2 quarts of antifreeze.
The new solution would have a total volume of 8 + <em>q</em> quarts, and it would contain a total amount of 3.2 + <em>q</em> quarts of antifreeze. You want to end up with a concentration of 60% antifreeze, which means
(3.2 + <em>q</em>) / (8 + <em>q</em>) = 0.60
Solve for <em>q</em> :
3.2 + <em>q</em> = 0.60 (8 + <em>q</em>)
3.2 + <em>q</em> = 4.8 + 0.6<em>q</em>
0.4<em>q</em> = 1.6
<em>q</em> = 4
Answer:
c
Step-by-step explanation:
Answer:
a. C= 5/9(F-32)
Step-by-step explanation:
you have to subtract 32 from both sides so that leaves you with f-32=9/5c and so then you need to multipy each side my 5/9 and that leaves yoh with 5/9(f-32)=c
Answer:

Step-by-step explanation:
Let the number be x
Given

Required
Find x

Collect Like Terms

Take LCM


Multiply both sides by 6


Divide both sides by -3


Hence, the number is 