Please help I’m in a hurry and need the answer!!

Mathematics

1 answer:

UkoKoshka [18]3 years ago

4 0

Answer:

56 cm Squared

Step-by-step explanation:

area of rectangle =10×5=50

area of smaller rectangle =3×2=6

area of the shape is 56

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There were 27 bales of hay in the barn. Grant stacked some more bales in the barn.Now there are 76 bales. Let b be the number of

lutik1710 [3]

Answer:

b=49

Step-by-step explanation:

27+b=76

76-27= 49

b=49

4 0

2 years ago

Find thhe remainder when 7^203 is divided by 4

Aleksandr [31]

Using the square-and-multiply approach, we have

$7^{203}=7\times(7^{101})^2$
$7^{101}=7\times(7^{50})^2$
$7^{50}=(7^{25})^2$
$7^{25}=7\times(7^{12})^2$
$7^{12}=(7^6)^2$
$7^6=(7^3)^2$
$7^3=7\times7^2$

and so, using the property that, if $a_1\equiv b_1\mod n$ and $a_2\equiv b_2\mod n$ , then $a_1a_2\equiv b_1b_2\mod n$ , we get

$7\equiv3\mod4$
$7^2\equiv9\equiv1\mod4$
$7^3\equiv7\times1\equiv7\equiv3\mod4$
$7^6\equiv9\equiv1\mod4$
$7^{12}\equiv1\mod4$
$7^{25}\equiv7\times1\equiv7\equiv3\mod4$
$7^{50}\equiv9\equiv1\mod4$
$7^{101}\equiv7\times1\equiv7\equiv3\mod4$
$7^{203}\equiv7\times9\equiv3\times1\equiv3\mod4$