solution is first os all find median
median is( 45+61)/2=53
find median of no in left of 53
it is 37
find median of no in right of 53
it is 64
now interquartile range=64-53=27
Thirty billion six hundred fifty thousand and eight
<span>The answer is six. Each line can intersect with each other line. If we call the lines A, B, C and D, imagine the intersections. Line A can intersect B, C and D - that's three. B can intersect A, C and D, but we have already counted where A and B intersect, so we just get another two. Then C can intersect A, B and D, but we have counted A-C and B-C already so we just get one more, where C and D intersect. So the answer is 3+2+1=6.</span>
The easiest way to solve this is to write the words mathematically. You're told that the product of 4 and a number, b = 3/5.
That means:
4b (product of 4 and b) =

To solve for b, you want to divide both sides by 4 to get the b by itself on the left of the equation:

----
Answer: b = 3/20
Answer:
Step-by-step explanation:
1) Separate terms with roots from terms without roots.
![x^2+4=\sqrt[\frac{1}{2} ]{4+1}](https://tex.z-dn.net/?f=x%5E2%2B4%3D%5Csqrt%5B%5Cfrac%7B1%7D%7B2%7D%20%5D%7B4%2B1%7D)
2) Simplify 4 + 1 to 5.
![x^2+4=\sqrt[\frac{1}{2} ]{5}](https://tex.z-dn.net/?f=x%5E2%2B4%3D%5Csqrt%5B%5Cfrac%7B1%7D%7B2%7D%20%5D%7B5%7D)
3) Invert and multiply.

4) Simplify
to 25.

5) Subtract 4 from both sides.

6) Simplify 25 - 1 to 24.

7) Take the square root of both sides.
