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d1i1m1o1n [39]
2 years ago
9

Find the sum of 8a+2b-4 and 3b-5. write. in expanded form and then standard form​

Mathematics
1 answer:
finlep [7]2 years ago
7 0

Answer:  2^3

Step-by-step explanation:

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What is this equation simplified<br><img src="https://tex.z-dn.net/?f=%20%28%7Bx%7D%5E%7B3%7D%292" id="TexFormula1" title=" ({x}
SVEN [57.7K]

Answer:

2x³

Step-by-step explanation:

2x³

5 0
2 years ago
Some people think it is unlucky if the 13th day of month falls on a Friday. show that in that there year (non-leap or leap) ther
Vlad1618 [11]
<span>There are several ways to do this problem. One of them is to realize that there's only 14 possible calendars for any year (a year may start on any of 7 days, and a year may be either a leap year, or a non-leap year. So 7*2 = 14 possible calendars for any year). And since there's only 14 different possibilities, it's quite easy to perform an exhaustive search to prove that any year has between 1 and 3 Friday the 13ths. Let's first deal with non-leap years. Initially, I'll determine what day of the week the 13th falls for each month for a year that starts on Sunday. Jan - Friday Feb - Monday Mar - Monday Apr - Thursday May - Saturday Jun - Tuesday Jul - Thursday Aug - Sunday Sep - Wednesday Oct - Friday Nov - Monday Dec - Wednesday Now let's count how many times for each weekday, the 13th falls there. Sunday - 1 Monday - 3 Tuesday - 1 Wednesday - 2 Thursday - 2 Friday - 2 Saturday - 1 The key thing to notice is that there is that the number of times the 13th falls upon a weekday is always in the range of 1 to 3 days. And if the non-leap year were to start on any other day of the week, the numbers would simply rotate to the next days. The above list is generated for a year where January 1st falls on a Sunday. If instead it were to fall on a Monday, then the value above for Sunday would be the value for Monday. The value above for Monday would be the value for Tuesday, etc. So we've handled all possible non-leap years. Let's do that again for a leap year starting on a Sunday. We get: Jan - Friday Feb - Monday Mar - Tuesday Apr - Friday May - Sunday Jun - Wednesday Jul - Friday Aug - Monday Sep - Thursday Oct - Saturday Nov - Tuesday Dec - Thursday And the weekday totals are: Sunday - 1 Monday - 2 Tuesday - 2 Wednesday - 1 Thursday - 2 Friday - 3 Saturday - 1 And once again, for every weekday, the total is between 1 and 3. And the same argument applies for every leap year. And since we've covered both leap and non-leap years. Then we've demonstrated that for every possible year, Friday the 13th will happen at least once, and no more than 3 times.</span>
5 0
2 years ago
Solve for x and explain how you got your answer <br> 3x + 4 = 16
12345 [234]

Answer:

X = 4

Step-by-step explanation:

3x=16-4

3x= 12

X=12/3

X= 4

5 0
3 years ago
Anyone who answers correctly gets brainlist!
Alex787 [66]

Answer:

B

Step-by-step explanation:

easy

3 0
2 years ago
Read 2 more answers
6²+(-4)<br> How do u get a answer
kiruha [24]
So 6^2 would be 36 because it is 6 times 6 and then -4 so 36-4=32
7 0
3 years ago
Read 2 more answers
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