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MrMuchimi
3 years ago
6

Serena lister all the possible three-digit numbers that can be created using each of the dígitos 7 , 8 and 9 only once. Which of

the following representa all the possible three digit numbers smallr than 900 that can beade using the digital 7 , 8 and 9 only once?
​
Mathematics
1 answer:
SpyIntel [72]3 years ago
4 0

Answer:

789 798 897 879

Step-by-step explanation:

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What is the value of 5 in 756? write and draw to explain how you know
Dennis_Churaev [7]
The value of 5 is 10 because it is in the tens place. If you draw a place value chart it shows that 5 is in the tens place. You could also draw it with 5 blocks with ten cubes.

Happy studying ^_^
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3 years ago
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Give the function 12x-16y=-48 determine the x-and y intercepts of the graph
Sholpan [36]
For the x-int, replace y with 0
for the y-int, replace x with 0

x-int:
12x-16(0)=-48
12x=-48
x=-4

y-int:
12(0)-16y=-48
-16y=-48
y=3
8 0
3 years ago
I will give brainliest to the person who answers all questions
stellarik [79]

Answer: Hope this helps!

Left to right - Q1 - Q5

1,500, 1,250, 0.25, 105, 25%

Step-by-step explanation:

Q1 - 15,000 * 0.02 * 5 = 1,500

Q2 - 25,000 * 0.01 * 5 = 1,250

Q3 - 20 - ((6 * 1) + (3 * 0.75) + (10 * 0.35) + (4 * 2)) = 0.25, 25 cents

Q4 - 30x + 1,000 = 4,200 (X = 107) Approximately 105 jobs

Q5 - 1,584 / (32 * 66) = 0.75 (75%) 100% - 75% = 25%

4 0
2 years ago
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The ratio of boys to girls in the ninth grade is 6:5. If there are 185 girls in the class, how many boys are there?
xeze [42]

Answer:

222 boys

Step-by-step explanation:

Let x = total number of ninth graders. By knowing how many students there are in the grade, we can find for the number of boys.

\frac{5}{6+5}x = 185 (number of girls in ninth grade)

\frac{5}{11}x = 185

x=407

To find for the number of boys, we can use substitution:

\frac{6}{6+5}x = \frac{6}{11}(407)

=222

∴ There are 222 boys in the class.

Hope this helps :)

8 0
3 years ago
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Pilar says that two linear systems below have the same solution. (see picture) Is she correct? Explain.
wariber [46]
The first set:

3x + 2y = 2  ---1)
5x + 4y = 6  ---2)

From 1), multiply all by 2, 6x + 4y = 4  ---3)

3) - 2),

6x + 4y - (5x + 4y) = 6 - 4
6x + 4y - 5x - 4y = 2
x = 2

Sub in x = 2 into 1),

3(2) + 2y = 2
2y = -4
y = -2

(2 , -2)


The second set:

3x + 2y = 2  ---1)
11x + 8y = 10  ---2)

From 1), multiply all by 4, 12x + 8y = 8 ---3)

3) - 2),

12x + 8y - (11x + 8y) = 8 - 10
12x + 8y - 11x - 8y = -2
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From this x value alone, we can tell that these two linear systems do NOT have the same solution as they meet at different coordinates.

Hope this helped! Ask me if there's any working from here that you don't understand! :)

5 0
3 years ago
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