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ivanzaharov [21]

2 years ago

12

Please help, I’m stuck on this one question.

1 answer:

Mamont248 [21]2 years ago

6 0

Answer:

D the last answer

Step-by-step explanation:

As X approaches positive or negative infinity, f(x) would approach negative infinity.

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200 is 25% of what number

Flura [38]

This is saying that 200 equals 25%. Set up a proportion like so. Remember that percent means per 100

200/x= 25/100

25*8=200
100*8=800=x

Final answer: 800

8 0

3 years ago

A swimming pool is represented on a coordinate grid with the following vertices: Vertex A is at (−2,−3) . Vertex B is at (−2,

Semmy [17]

Answer:

26 yards.

Step-by-step explanation:

We can find the distance walked by Jared by finding the distances between each of the given vertex of swimming pool. We will use distance formula to find the distances between each vertex.

$\text{Distance}=\sqrt{(x_2-x_1)^{2}+(y_2-y_1)^{2}}$

$\text{Distance between vertex A and vertex B}=\sqrt{(-2--2)^{2}+(-3-5)^{2}}$

$\text{Distance between vertex A and vertex B}=\sqrt{(-2+2)^{2}+(-8)^{2}}$

$\text{Distance between vertex A and vertex B}=\sqrt{(0)^{2}+(-8)^{2}}$

$\text{Distance between vertex A and vertex B}=\sqrt{64}=8$

Now let us find distance between vertex B and vertex C.

$\text{Distance between vertex B and vertex C}=\sqrt{(-2-3)^{2}+(5-5)^{2}}$

$\text{Distance between vertex B and vertex C}=\sqrt{(-5)^{2}+(0)^{2}}$

$\text{Distance between vertex B and vertex C}=\sqrt{25}=5$

Now let us find distance between vertex C and vertex D.

$\text{Distance between vertex C and vertex D}=\sqrt{(3-3)^{2}+(5--3)^{2}}$

$\text{Distance between vertex C and vertex D}=\sqrt{(0)^{2}+(5+3)^{2}}$

$\text{Distance between vertex C and vertex D}=\sqrt{64}=8$

Now let us find distance between vertex D and vertex A.

$\text{Distance between vertex D and vertex A}=\sqrt{(3--2)^{2}+(-3--3)^{2}}$

$\text{Distance between vertex D and vertex A}=\sqrt{(3+2)^{2}+(-3+3)^{2}}$

$\text{Distance between vertex D and vertex A}=\sqrt{(5)^{2}+(0)^{2}}$

$\text{Distance between vertex D and vertex A}=\sqrt{25}=5$

Now let us add all these distances to find the total distance walked by Jared.

$\text{Total distance walked by Jared}=8+5+8+5$

$\text{Total distance walked by Jared}=26$

Since we have been given that one unit on the grid equals 1 yard, therefore, Jared walked a distance equal to 26 yards.

3 0

3 years ago

If corresponding angles are on parallel lines, then their measure is the same _____.

weqwewe [10]

Step-by-step explanation:

always .

plz mark my answer as brainlist.hope this will be helpful to you

6 0

2 years ago

Read 2 more answers

I need help ASAP marking brainliest

Thepotemich [5.8K]

Answer: option D -1,0,2

Step-by-step explanation:

2^x-2

When x=0

We have 2^0-2

1-2=-1

when x=1

We have 2^1-2

2-2=0

When x=2

We have 2^2-2

4-2=2

6 0

3 years ago

Read 2 more answers

You are converting 8 centimeters to meters

morpeh [17]

Answer:

8cm = 0.08m

Step-by-step explanation:

8×10^-2 Because we convert

from cm to m.

8 0

3 years ago

Read 2 more answers