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ivanzaharov [21]
3 years ago
12

Please help, I’m stuck on this one question.

Mathematics
1 answer:
Mamont248 [21]3 years ago
6 0

Answer:

D the last answer

Step-by-step explanation:

As X approaches positive or negative infinity, f(x) would approach negative infinity.

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Trigonometric Identities and Applications? help
Vadim26 [7]
\bf h=-15cos\left( \frac{2\pi }{5}t \right)\qquad \boxed{h=8}\qquad 8=-15cos\left( \frac{2\pi }{5}t \right)
\\\\\\
\cfrac{8}{-15}=cos\left( \frac{2\pi }{5}t \right)\implies cos^{-1}\left(  \frac{8}{-15}\right)=cos^{-1}\left[ cos\left( \frac{2\pi }{5}t \right) \right]
\\\\\\
cos^{-1}\left(  \frac{8}{-15}\right)=\cfrac{2\pi }{5}t\implies \cfrac{5}{2\pi }\cdot  cos^{-1}\left(  \frac{8}{-15}\right)=t\\\\
-------------------------------

\bf cos^{-1}\left(  \frac{8}{-15}\right)=\stackrel{radians}{\stackrel{II~quadrant}{\approx 2.13}~~,~~\stackrel{III~quadrant}{\approx 4.15}}\qquad \qquad 
t=
\begin{cases}
\frac{5}{2\pi }\cdot 2.13\\\\
\frac{5}{2\pi }\cdot 4.15
\end{cases}
3 0
3 years ago
obesity: The National Center for Health Statistics conducted the National Health Interview Survey (NHIS) for 27,787 U.S. civilia
WARRIOR [948]

Answer:

False.

Step-by-step explanation:

Hello!

29.9% is the proportion of adults aged 20 and over that were obese in January - September 2014.

This percentage was obtained from a sample of 27 787 adults, it's not a parameter but an estimation of the population proportion obtained from this sample.

I hope it helps!

5 0
3 years ago
Logan opened a savings account 21 years ago with a deposit of $3,471.52. The account has an interest rate of 3.1% compounded mon
notka56 [123]
P = $3,471.52, the principal
r = 3.1% = 0.031, annual ratr
n = 12, monthly compounding
t = 21 years

Note that n*t = 252.

The value after 21 years is
A = 3471.52*(1 + 0.031/12)²⁵²
   = $6,650.91

The interest earned is
6650.91 - 3471.52 = 3179.39

Answer: $3,179.39
8 0
3 years ago
Free points, solve 4b+5b=8b-1+3b+15?​
vazorg [7]

Answer: Hi!

First, we should combine like terms:

4b + 5b = 8b − 1 +3b + 15 =

9b = 11b + 14

Now, we should subtract 11b from both sides.

-2b = 14

Now, we should divide both sides by -2.

b = -7

Hope this helps!

6 0
3 years ago
Read 2 more answers
A sock drawer contains eight navy blue socks and five black socks with no other socks. If you reach in the drawer and take two s
Rzqust [24]

Answer:

a. the probability of picking a navy sock and a black sock = P (A & B)

= (8/13 ) * (5/12) = 40/156 = 0.256

b. the probability of picking two navy or two black is

= 56/156 + 20/156 = 76/156 = 0.487

c. the probability of either 2 navy socks is picked or one black  & one navy socks.

= 40/156 + 56/156 = 96/156 = 0.615

Step-by-step explanation:

A sock drawer contains 8 navy blue socks and 5 black socks with no other socks.

If you reach in the drawer and take two socks without looking and without replacement, what is the probability that:  

Solution:

total socks = N = 8 + 5 + 0 = 13

a) you will pick a navy sock and a black sock?

Let A be the probability of picking a navy socks first.

Then P (A) = 8/13

without replacing the navy sock, will pick the black sock, total number of socks left is 12.

Let B be the probability of picking a black sock again.

 P (B) = 5/12.

Then, the probability of picking a navy sock and a black sock = P (A & B)

= (8/13 ) * (5/12) = 40/156 = 0.256

b) the colors of the two socks will match?

Let A be the probability of picking a navy socks first.

Then P (A) = 8/13

without replacing the navy sock, will pick another navy sock, total number of socks left is 12.

Let B be the probability of another navy sock again.

 P (B) = 7/12.

Then, the probability of picking 2 navy sock = P (A & B)

= (8/13 ) * (7/12) = 56/156 = 0.359

Let D be the probability of picking a black socks first.

Then P (D) = 5/13

without replacing the black sock, will pick another black sock, total number of socks left is 12.

Let E be the probability of another black sock again.

 P (E) = 4/12.

Then, the probability of picking 2 black sock = P (D & E)

= (5/13 ) * (4/12) = 5/39 = 0.128

Now, the probability of picking two navy or two black is

= 56/156 + 20/156 = 76/156 = 0.487

c) at least one navy sock will be selected?

this means, is either you pick one navy sock and one black or two navy socks.

so, if you will pick a navy sock and a black sock, the probability of picking a navy sock and a black sock = P (A & B)

= (8/13 ) * (5/12) = 40/156 = 0.256

also, if you will pick 2 navy sock, Then, the probability of picking 2 navy sock = P (A & B)

= (8/13 ) * (7/12) = 56/156 = 0.359

now either 2 navy socks is picked or one black  one navy socks.

= 40/156 + 56/156 = 96/156 = 0.615

4 0
3 years ago
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