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Georgia [21]
3 years ago
8

Find the width of a rectangular prism when the surface area is 208 square centimeters -H=8cm,L=6cm

Mathematics
2 answers:
alexandr1967 [171]3 years ago
7 0
Area=2area\ of\ base+4\area\ of\ side\\\\
area\ of\ base=2width*L=12width\\\\
area\ of\ side=2width*8+2*6*8=96+16width\\\\
208=96+16width+12width\\\\
208=96+28width\ \ \ |Subtract \ 96\\\\112=28width\ \ \ |Divide\ by\ 28\\\\width=4cm

il63 [147K]3 years ago
3 0
By definition, the surface area of a rectangular prism is given by:
 A = 2wl + 2wh + 2hl

 Where,
 w: width of the prism
 h: prism height
 l: length of the prism
 Clearing w we have:
 A = 2 (wl + wh + hl)

 A=2w(l + h)+2hl
 w=\frac{A - 2hl}{2(l + h)}
 Substituting values we have:
 w=\frac{208 - 2(8)(6)}{2(6 + 8)}
 Rewriting:
 w=\frac{208 - 96}{2(14)}
 w=\frac{112}{28}
 w = 4
 Answer:
 
the width of the rectangular prism is:
 
w = 4
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n(A)-n(A\cap B)-n(A\cap C)+n(A\cap B\cap C)=9\\\\\Rightarrow n(A\cap B)+n(A\cap C)=24+p~~~~~~~~~~~~~~(a),\\\\n(A\cap B)+n(B\cap C)=20+p~~~~~~~~~~~~~~(b),\\\\n(B\cap C)+n(A\cap C)=20+p~~~~~~~~~~~~~~~(c).

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n(A\cap B)=n(A\cap C)=14.

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n(A\cap B\cap C)=4 and

n(A\cup B\cup C)=n(A)+n(B)+n(C)-n(A\cap B)-n(B\cap C)-n(A\cap C)+n(A\cap B\cap C)\\\\\Rightarrow n(A\cap B\cap C)=33+32+40-9-12-20+4\\\\\Rightarrow n(A\cap B\cap C)=68.

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3 years ago
A pack of folders has a length of 5 inches, a width of 12 inches, and a height of 1 inch. The pack of folders will be shipped in
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Answer:

A) Each pack of folders has a volume of 60 cubic inches.

B) The box has a volume of about 720 cubic inches

D) If the box help 20 packs of folders, it would have a volume of about 1,200 cubic inches.

Step-by-step explanation:

<em><u>Verify each statement</u></em>

<em>A) Each pack of folders has a volume of 60 cubic inches.</em>

The statement is True

Because

The volume of each pack of folders is equal to

V=(5)(12)(1)=60\ in^{3}

<em>B) The box has a volume of about 720 cubic inches</em>

The statement is True

Because

The volume of the box is equal to the volume  of one pack of folders multiplied by 12

so

V=(12)60=720\ in^{3}

<em>C) If the box held 15 packs of folders, it would have a volume of about 1,200 cubic inches</em>

The statement is False

Because

Applying proportion

\frac{12}{720}\frac{packs}{in^{3}}=\frac{15}{x}\frac{packs}{in^{3}}\\ \\x=720*15/12\\ \\x=900\ in^{3}

900\ in^{3}\neq 1,200\ in^{3}

<em>D) If the box help 20 packs of folders, it would have a volume of about 1,200 cubic inches.</em>

The statement is True

Because

Applying proportion

\frac{12}{720}\frac{packs}{in^{3}}=\frac{20}{x}\frac{packs}{in^{3}}\\ \\x=720*20/12\\ \\x=1,200\ in^{3}

1,200\ in^{3}= 1,200\ in^{3}

<em>E) Each pack of folders has a volume of 24 cubic inches.</em>

The statement is False

Because

The volume of each pack of folders is equal to

V=(5)(12)(1)=60\ in^{3}

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