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OverLord2011 [107]
3 years ago
15

A rectangle has a length of (x+10) centimeters and a width of x centimeters. If the perimeter is 32 centimeters, what is the len

gth of the rectangle?
Mathematics
1 answer:
I am Lyosha [343]3 years ago
7 0

Given:

Length of rectangle = (x+10) cm

Width of the rectangle = x cm

Perimeter = 32 cm

To find:

The length of the rectangle.

Solution:

We know that,

Perimeter=2(l+w)

Where, l is length and w is width.

Substituting the values, we get

32=2((x+10)+x)

32=2(2x+10)

32=4x+20

Subtract 20 from both sides.

32-20=4x

12=4x

Divide both sides by

3=x

So, the length is

3+10=13

Therefore, the length of the rectangle is 13 cm.

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Solve x2 + 5x = −6. x = 5 and x = 1 x = −5 and x = −1 x = 3 and x = 2 x = −3 and x = −2
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Answer:

x = −3 and x = −2

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Which expression below is equivalent to -3x+5(x+2)
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                5x + 5 * 2

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4 0
3 years ago
Suppose a circle has a radius of 13 inches. How far would a 24 inch chord be from the center of the circle? (Hint: Draw a diagra
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Answer:

Step-by-step explanation:

Directions

  • Draw a circle
  • Dear a chord with a length of 24 inside the circle. You just have to label it as 24
  • Draw a radius that is perpendicular and a bisector through the chord
  • Draw a radius that is from the center of the circle to one end of the chord.
  • Label where the perpendicular radius to the chord intersect. Call it E.
  • You should get something that looks like  the diagram below. The only thing you have to do is put in the point E which is the midpoint of CB.

Givens

AC = 13 inches                   Given

CB = 24 inches                  Given

CE = 12 inches                    Construction and property of a midpoint.

So what we have now is a right triangle (ACE) with the right angle at E.

What we seek is AE

Formula

AC^2 = CE^2 + AE^2

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169 - 144 = 144-144 + AE^2     Combine

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√25 = √AE^2

5 = AE

Answer

The 24 inch chord is 5 inches from the center of the circle.

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