The coordinates of four points on the line are (0,-5), (3,-3), (6,-1) and (9,1)
<h3>How to determine the coordinates?</h3>
The given parameters are given as:
- Slope, m = 2/3
- y-intercept, c = -5
The equation is represented as:
y = mx + c
So, we have:
y = 2/3x -5
When x = 0, we have;
y = 2/3 * 0 -5 = -5
When x = 3, we have;
y = 2/3 * 3 -5 = -3
When x = 6, we have;
y = 2/3 * 6 -5 = -1
When x = 9, we have;
y = 2/3 * 9 -5 = 1
Hence, the coordinates of four points on the line are (0,-5), (3,-3), (6,-1) and (9,1)
Read more about linear equations at:
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Answer:
<u>x = 8 and y = 5</u>
Step-by-step explanation:
The question is as following:
what is x and y for the following system of equations:
50x + 30 y = 550 ⇒ (1)
44x + 36 y = 532 ⇒ (2)
Subtract (1) - (2)
∴ 6x - 6y = 18
Divide both sides by 6
∴ x - y = 3
∴ x = 3 + y ⇒ (3)
Substitute with the value of x at (1)
50(3+y) + 30y = 550
Solve for y
150 + 50y + 30y = 550
80y = 550 - 150 = 400
∴ y = 400/80 = 5
Substitute with the value of y at (3)
∴ x = 3 + y = 3 + 5 = 8
<u>So, x = 8 and y = 5</u>
2 x 10 to the 3rd power is
2x10^3
Total of number= 10
Number of A's=3
3/10 = 0.3
The answer is already in simplest
Answer: BC = 54 <kjm=44
Step-by-step explanation:
1st 0ne-
if you look at it as 2 triangles with D being the shared side- I can determine that the angles are congruent (by SSA theorem)
so
6x=9x-27 (by corresponding parts of congruent Theorem)
-3x=-27
x=9
BC- 9(9)-27= 81-27=54
2nd one-
J bisects KJM
4x+6=3x+10
x=4
3(4)+10= 22
4(4)+6= 22
KJM= 22+22= 44