Suppose a circle has a radius of 13 inches. How far would a 24 inch chord be from the center of the circle? (Hint: Draw a diagra m) PLEASE PLEASE HELPPPP
2 answers:
Answer:
Step-by-step explanation:
Directions
Draw a circle Dear a chord with a length of 24 inside the circle. You just have to label it as 24 Draw a radius that is perpendicular and a bisector through the chord Draw a radius that is from the center of the circle to one end of the chord. Label where the perpendicular radius to the chord intersect. Call it E. You should get something that looks like the diagram below. The only thing you have to do is put in the point E which is the midpoint of CB. Givens
AC = 13 inches Given
CB = 24 inches Given
CE = 12 inches Construction and property of a midpoint.
So what we have now is a right triangle (ACE) with the right angle at E.
What we seek is AE
Formula
AC^2 = CE^2 + AE^2
13^2 = 12^2 + AE^2
169 = 144 + AE^2 Subtract 144 from both sides.
169 - 144 = 144-144 + AE^2 Combine
25 = AE^2 Take the square root of both sides
√25 = √AE^2
5 = AE
Answer
The 24 inch chord is 5 inches from the center of the circle.
Answer:
24 Inches
Step-by-step explanation:
Its 24 Inches away from the centre lol
You might be interested in
40×8=320[ 8×3=24 ]320+24=344
Your answer is negative 32.24.
80 percent of 52.5 percent of the trip is 42 percent therefore, 4 hours and 12 min (or 252 min) is 42 percent of the trip so 252/.42 = x/1 x = 600 min the whole trip was 10 hours
I think hypotenuse is A 55 feet
Your answer is C. Think of the x axis as the ground.