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Anuta_ua [19.1K]
3 years ago
9

PLS HELP WITH THIS QUESTION

Mathematics
2 answers:
Anna [14]3 years ago
6 0
Y is equal to 46 degrees
alexandr1967 [171]3 years ago
4 0
ANSWER: y=6
straight lines are 180° and all the angles in a triangle add up to 180°
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If QS bisects PQT, SQT=(8x- 25),PQT=(9x+34), and SQR=112, find each measure.
Goryan [66]

The values of the angles are; x = 12°, m∠PQS = 71°, m∠PQT = 142° and m∠TQR = 41°

<h3>What are the measure of the each angle?</h3>

The required angles; x, m∠PQS, m∠PQT, and m∠TQR

The given parameters are bisects ∠PQT

m∠SQT = (8·x - 25)°

m∠PQT = (9·x + 34)°

m∠SQR = 112°

We have;

m∠PQT = m∠SQT + m∠PQS (Angle addition postulate)

m∠SQT ≅ m∠PQS (Angles formed by angle bisector are congruent)

m∠SQT = m∠PQS  by Definition of congruency

m∠PQT = 2 × m∠SQT

Therefore;

(9·x + 34)° = 2 × (8·x - 25)° = (16·x - 50)°

Collecting like terms gives:

(34 + 50)° = 16·x - 9·x = 7·x

7·x = 84°

x = 84°/7 = 12°

x = 12°

m∠SQT = (8·x - 25)°

Therefore;

m∠SQT = (8 × 12 - 25)° = 71°

m∠SQT = 71°

m∠PQT = 2 × m∠SQT

∴ m∠PQT = 2 × 71° = 142°

m∠PQT = 142°

m∠PQS = m∠SQT (Angles formed by the same bisector )

∴ m∠PQS = m∠SQT = 71°

m∠PQS = 71°

m∠SQR = m∠SQT + m∠TQR (Angle addition postulate)

m∠SQT = 71°

∴  m∠SQR = 112° = 71° + m∠TQR

m∠TQR = 112° - 71° = 41°

m∠TQR = 41°

Learn more about angles here:

brainly.com/question/2882938

#SPJ1

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"John spent $30 on six toy cars. How much did each toy car cost? Write a one step equation. Solve"
Alika [10]
John spent 30 on six cars 5 times 6 = 30
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3 years ago
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A candy is in the shape of a sphere. The candy has a radius of 1.5 centimeters. Which of the following is closest to the volume
LenaWriter [7]

Answer:

The answer would be 14 cm

V = \frac{4pi(1.5)^3}{3}

4.5pi = 14.3

(pi = π)

Your welcome :)

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2 years ago
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Which equation exemplifies the commutative property of multiplication??
Iteru [2.4K]
The answer is 1.

EXPLANATION

The commutative property of multiplication states that two numbers can be multiplied in either order.
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4 years ago
1.3( x + 2 )-( y - 6) <br> Help please
mestny [16]
Basically, we need to plug in the given values for the variables x and y into the given expression 1.3(x+2)-(y-6). First off, we can plug in all the given values into the expression, giving us 1.3(4+2)-(2-6). Now, perform the operations on the inside of the parentheses. Doing this, we get 1.3(6)-(-4). Now, we use the distributive property to simplify. This gives us 7.8+4. Finally, when we add the two numbers, we get \boxed{11.8}. Hope this helped!
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