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kirill115 [55]
3 years ago
9

1)Given: AB = 4 AD = 6

Mathematics
1 answer:
Vaselesa [24]3 years ago
5 0
<span>1)Given: AB = 4 AD = 6
What is the name of the radius of the larger circle?
the answer part 1) is 
the radius </span>of the larger circle is AD

<span>2)Given: AB = 4 AD = 6
What point is in the interior of both circles?
the answer Part 2) is 
The point A  (the center of the circles)

</span><span>3) Given: AB = 4 AD = 6
Which points are in the exterior of both circles?</span><span>
the answer Part 3) is
</span><span>E and G

</span><span>4)The circles are _____.
</span><span>the answer Part 4) is
</span><span>concentric
</span>
<span>5)If AC = 20 and BD = 8, what is the radius of the smaller circle?
</span>we know that
radius smaller circle=AB
and
AB=AC-BD--------> AC=20-12-------> AC=8 units

the answer part 5) is
the radius of the smaller circle is 12 units

<span>6)Given: AB = 4 AD= 6
What is the length of BD?</span>
we know that
AD=AB+BD
solve for BD
BD=AD-AB--------> BD=6-4-----> BD=2 units

the answer Part 6) is
the length of BD is 2

<span>7)Given: AB = 4 AD = 6
What is the name of the radius of the smaller circle?</span>

the answer Part 7) is 
the name of the radius of the smaller circle is AB
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C= Cost
g= # of times games played

C = 0.50g + 3

C(0) = 0.50(0) + 3
C(0) = 0 + 3
C(0) = 3

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abruzzese [7]

Answer:

(a) P(Y'|M)\approx 0.3297

(b) P(Y|M')\approx 0.8323

(c) P(Y'|M')\approx 0.1323

Step-by-step explanation:

Given table is

                Yes      No      Don't Know      Total

Men          162      92             25               279

Women      258    41              11               310

Total          420    133            36                589

According the the conditional probability, if A and B are two event then

P(A|B)=P(\frac{A}{B})=\frac{P(A\cap B)}{P(B)}

We need to find the following probabilities.

Let Y is the event "saying yes," and M is the event "being a man."

(a)

P(Y'|M)=\frac{P(Y'\cap M)}{P(M)}

P(Y'|M)=\frac{\frac{92}{589}}{\frac{279}{589}}

P(Y'|M)=\frac{92}{279}

P(Y'|M)=0.329749103943

P(Y'|M)\approx 0.3297

(b)

P(Y|M')=\frac{P(Y\cap M')}{P(M')}

P(Y|M')=\frac{\frac{258}{589}}{\frac{310}{589}}

P(Y|M')=\frac{258}{310}

P(Y|M')=0.832258064516

P(Y|M')\approx 0.8323

(c)

P(Y'|M')=\frac{P(Y'\cap M')}{P(M')}

P(Y'|M')=\frac{\frac{41}{589}}{\frac{310}{589}}

P(Y'|M')=\frac{41}{310}

P(Y'|M')=0.132258064516

P(Y'|M')\approx 0.1323

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Step-by-step explanation:

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Step-by-step explanation:

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