Question

HELPPP THIS IS URGENT!

Answer 1

Answer:

see below

Step-by-step explanation:

$y=-3(x-4)^2+2$

$x=-3(y-4)^2+2$

$x-2=-3(y-4)^2$

$\frac{1}{3}(2-x) =(y-4)^2$

$\sqrt{\frac{1}{3}(2-x)}=y-4$

$f^{-1}(x)=\sqrt{ \frac{1}{3}(2-x)}+4$