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yawa3891 [41]
2 years ago
6

HELPPP THIS IS URGENT!

Mathematics
1 answer:
Zinaida [17]2 years ago
8 0

Answer:

see below

Step-by-step explanation:

y=-3(x-4)^2+2

x=-3(y-4)^2+2

x-2=-3(y-4)^2

\frac{1}{3}(2-x) =(y-4)^2

\sqrt{\frac{1}{3}(2-x)}=y-4

f^{-1}(x)=\sqrt{ \frac{1}{3}(2-x)}+4

           

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Please help!!!
VikaD [51]

Answer:

a.

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b.

Maximum at: x = 0, π and 2π

Minimum at: x = π/2 and 3π/2

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Step-by-step explanation:

Part a:

Amplitude represents the half of the distance between the maximum point and the minimum point of the function. So the easy way to find the amplitude is: Find the difference between maximum and minimum value of the function and divide the difference by 2.

So, amplitude will be: \frac{Maximum-Minimum}{2}=\frac{4-(-4)}{2}=\frac{8}{2}=4

Therefore, the amplitude of the function is 4.

Period is the time in which the function completes its one cycle. From the graph we can see that cosine started at 0 and completed its cycle at π. After π the same value starts to repeat. So the period of the given cosine function is π.

Part b:

From the graph we can see that the maximum values occur at the following points: x = 0, π and 2π

The scale on x-axis between 0 and π is divided into 4 squares, so each square represents π/4

Therefore, the minimum value occurs at x = π/2 and 3π/2

Zeros occur where the graph crosses the x-axis. So the zeros occur at the following points: π/4, 3π/4, 5π/4 and 7π/4

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nadya68 [22]
For this case, the first thing you should do is to know the following transformation:
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 Answer:
 
13 pi / 6 as a function of an angle in quadrant i is:
 
30 degrees
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4 years ago
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Umnica [9.8K]
4,3 hope it help the top is 4 and the bottom is 3
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2 years ago
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