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choli [55]
3 years ago
7

Y'all if you know how to do this math question pls help me out

Mathematics
1 answer:
Nana76 [90]3 years ago
7 0

Answer:

<em>5i * 7i = 64</em>

Step-by-step explanation:

<em>i </em>stands for inches, but Ion kno if that's the variable u need. But what I did makes the most sense. But Ion kno if it's right cuz that's my best guess, so y'all don't be gettin mad if it's wrong.

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You recently borrowed $500 from a friend. You signed a contract that requires you to pay back one third of the loan every month
tester [92]

The amount of money I would repay in the first month is $166.67.

The amount of money I would repay in the second month is $166.67.

The amount of money I would repay in the third month is $166.66.

<h3>How much would I repay each month?</h3>

In order to determine the money that would be repaid each of the first two months, multiply 1/3 by the amount of the loan.

1/3 x $500 = $166.67

Amount to be repaid in the third month = $500 - (166.67 x 2) = $166.66

To learn more about loans, please check: brainly.com/question/25811386

8 0
2 years ago
6x+5y+2z=41<br> 4x-10z=-10<br> -x-2y+2z=-1
Rasek [7]
\left[x \right] = \left[ \frac{5\,y}{158}+\frac{6\,z}{79}\right][x]=[​158​​5y​​+​79​​6z​​]
3 0
3 years ago
BRAINLIEST!!!
goldenfox [79]

Answer:  \frac{8}{17} or 8:17

Step-by-step explanation:

For any angle x (other than right angle) in a right triangle ,the trigonometric ratio of sin x is given by :-

\sin x=\frac{\text{side opposite to x}}{\text{Hypotenuse}}

Given: A right triangle with hypotenuse = 68 units

The side adjacent to S =  60

Let h be the side opposite to S, then using Pythagoras in the given right triangle, we get

(68)^2=60^2+h^2\\\\\Rightarrow\ h^2=68^2-60^2\\\\\Rightarrow\ h^2=1024\\\\\Rightarrow\ h=\sqrt{1024}=32

Thus, the side opposite to S = 32 units

Now,  the trigonometric ratio for sin S is given by :-

\sin S=\frac{\text{side opposite to S}}{\text{Hypotenuse}}\\\\\Rightarrow\sin S=\frac{32}{68}=\frac{8}{17}

Hence, the  trigonometric ratio for sin S =\frac{8}{17} or 8:17

5 0
3 years ago
If ADEF is reflected over the x-axis, what would be the coordinates of point F?
Brut [27]

Answer:

Please check the explanation.

Step-by-step explanation:

Let the coordinates of the point F be (x, y).

When a point F(x, y) is reflected over the x-axis, the x-coordinate of the point F remains the same, and the y-coordinate of the point reverses the sign.

Thus, the rule of reflection over the x-axis:

F(x, y)   →    F'(x, -y)

Here,

F'(x, -y) would be coordinates of point F after the reflection over the x-axis.

Let say, the point F(1, 2).

The coordinate of the point F after the reflection over the x-axis would be:

F(1, 2)   →    F'(1, -2)

Thus, F'(1, -2) would be the coordinates of point F after the reflection over the x-axis.

6 0
3 years ago
Pls help asap..thank you!
tia_tia [17]

Answer:

5.25

Step-by-step explanation:

If CD is perpendicular to AB, a right angle is formed by the perpendicular lines at the base of the triangle. If we know that AB is 3 we can divided that by two to use half the triangle and create a right trianle with a base of 1.5 (half of 3) a height of rad 3 now all we have to do is use P-Thags to find AC which is the hypotenuse. After doing 1.5 squared + rad 3 squared = ac squared you will get the answer of AC = 5.25

7 0
3 years ago
Read 2 more answers
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