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Brums [2.3K]
3 years ago
9

GM EVERYONE IT'S ALMOST FRIDAYYYYY!!

Mathematics
2 answers:
Talja [164]3 years ago
6 0

Answer:

Good morning ikr :)

Step-by-step explanation:

thx for the points

tester [92]3 years ago
3 0

Answer

Good morning, I loveeeee FRIDAYSSSSS!!!!

Step-by-step explanation:

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Please answer the question correctly with factual information for brainliest.
Phantasy [73]

Answer:

8.9

Step-by-step explanation:

1)\ S = 80 => l = \sqrt{80}

2)\ l = \sqrt{80} = 8.9

4 0
3 years ago
Find the midpoint of the segment with the given endpoints K(-2,-4) and L(-4,6)
Ilia_Sergeevich [38]

\bf ~~~~~~~~~~~~\textit{middle point of 2 points } \\\\ K(\stackrel{x_1}{-2}~,~\stackrel{y_1}{-4})\qquad L(\stackrel{x_2}{-4}~,~\stackrel{y_2}{6}) \qquad \left(\cfrac{ x_2 + x_1}{2}~~~ ,~~~ \cfrac{ y_2 + y_1}{2} \right) \\\\\\ \left( \cfrac{-4-2}{2}~~,~~\cfrac{6-4}{2} \right)\implies \left( \cfrac{-6}{2}~~,~~\cfrac{2}{2} \right)\implies (-3~,~1)

8 0
3 years ago
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Write a quadratic function f whose zeros are 3 and -10.<br> f(x) =
andreyandreev [35.5K]

Answer:

f(x)= x^2 + 7x - 30

5 0
3 years ago
For fun question
ZanzabumX [31]
Consider the function f(x)=x^{1/3}, which has derivative f'(x)=\dfrac13x^{-2/3}.

The linear approximation of f(x) for some value x within a neighborhood of x=c is given by

f(x)\approx f'(c)(x-c)+f(c)

Let c=64. Then (63.97)^{1/3} can be estimated to be

f(63.97)\approxf'(64)(63.97-64)+f(64)
\sqrt[3]{63.97}\approx4-\dfrac{0.03}{48}=3.999375

Since f'(x)>0 for x>0, it follows that f(x) must be strictly increasing over that part of its domain, which means the linear approximation lies strictly above the function f(x). This means the estimated value is an overestimation.

Indeed, the actual value is closer to the number 3.999374902...
4 0
3 years ago
the tile shown has a side length of 10.5 inches what power can you write to represent the area of the tile
Sliva [168]
You could not do that then you would gey 110.25 which is what is not the question
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3 years ago
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