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bija089 [108]
3 years ago
5

Find the length of the third side to the nearest tenth 7 1

Mathematics
1 answer:
AlexFokin [52]3 years ago
3 0

Answer:

10.7

Step-by-step explanation:

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19. Given m29 = 2x + 3, m27 = 3x – 9, and m/1 = x + 18, ,<br> what is the value of x?
Crank

Answer:

15

Step-by-step explanation:

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In considering career options, Ella would like to enter an industry with at least 50% growth from 2000 to 2010. Based on the abo
AlladinOne [14]

Answer:

Industries below 50% growth are

Personnel supply services, Warehousing and storage, Water and sanitation, Management and public relations, Business services, Equipment rental and leasing.

Step-by-step explanation:

In the graph percentage change is on the x axis and on the y axis all industries have been mentioned.

All the industries on y axis have the span over x axis representing the growth and salaries.

Out of 10 top industries only four industries have the growth of 50% which is evident from the graph.Those industries are Health Services,Computer and data processing, Cable television services and Residential care. Rest six industries are below 60% growth.So Ella should consider these industries to join.

8 0
3 years ago
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Morgan has an 8-foot board that must be cut into boards that are feet long. How many of the smaller boards can he get from the 8
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Just multiply all the eights
6 0
3 years ago
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Why do fractions need to have a common denominator before you add or subtract them?
djyliett [7]
Fractions need common denominator to add or subtract them because without denominators a fraction is not a fraction, it is a whole number
Example - 2/8 is a fraction
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5 0
3 years ago
Element X decays radioactively with a half-life of eight minutes. If there are 800 g of element X, how long, to the nearest 10th
Harman [31]

Answer: 41.5 min

Step-by-step explanation:

This problem can be solved with the Radioactive Half Life Formula:  

A=A_{o}.2^{\frac{-t}{h}} (1)

Where:  

A=22 g is the final amount of the radioactive element

A_{o}=800 g is the initial amount of the radioactive element  

t is the time elapsed  

h=8 min is the half life of the radioactive element  

So, we need to substitute the given values and find t from (1):  

22 g=(800 g) 2^{\frac{-t}{8 min}} (2)  

\frac{22 g}{800 g}=2^{\frac{-t}{8 min}} (3)  

\frac{11}{400}=2^{\frac{-t}{8 min}} (4)  

Applying natural logarithm in both sides:  

ln(\frac{11}{400})=ln(2^{\frac{-t}{8 min}}) (5)  

-3.593=-\frac{t}{8 min}ln(2) (6)  

Clearing t:

t=41.46 min \approx 41.5 min This is the time elapsed

7 0
3 years ago
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