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Karolina [17]
3 years ago
9

Aye plz help. Im abt to die. Find the perimiter of the shape below.

Mathematics
1 answer:
Law Incorporation [45]3 years ago
4 0

Answer:

40

Step-by-step explanation:

Add all the sides together which is 40

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85<br>What number goes where the<br>question mark is? ​
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Answer:

I DONT UNDERSTAND

Step-by-step explanation:

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3 years ago
A zip line starts on a platform that is 40 meters above the ground. The anchor for the zip line is 198 horizontal meters from th
Damm [24]

Answer:

Solution given:

perpendicular distance =height [p]=40m

base or horizontal distance [b]=198m

Hypotenuse or zip line [h]=?

Now

By using Pythagoras law

h²=p²+b²

h²=40²+198²

h=√40804

h=202m

<u>So</u><u> </u><u>the</u><u> </u><u>Zip</u><u> </u><u>line</u><u> </u><u>is</u><u> </u><u>2</u><u>0</u><u>2</u><u>m</u><u> </u><u>long</u><u>.</u>

7 0
3 years ago
Red blood cells diffuse gas in and out of the bloodstream. Find the surface to volume ratio for a red blood cell using the infor
Tems11 [23]

Answer:

1.29

Step-by-step explanation:

6 0
3 years ago
Brian invests ?1900 into a savings account. The bank gives 3.5% compound interest for the first 2 years and 4.9% thereafter. How
Scorpion4ik [409]

let's check how much is it after 2 years firstly.


\bf ~~~~~~ \textit{Compound Interest Earned Amount} \\\\ A=P\left(1+\frac{r}{n}\right)^{nt} \quad \begin{cases} A=\textit{accumulated amount}\\ P=\textit{original amount deposited}\dotfill &1900\\ r=rate\to 3.5\%\to \frac{3.5}{100}\dotfill &0.035\\ n= \begin{array}{llll} \textit{times it compounds per year}\\ \textit{yearly, thus once} \end{array}\dotfill &1\\ t=years\dotfill &2 \end{cases} \\\\\\ A=1900\left(1+\frac{0.035}{1}\right)^{1\cdot 2}\implies A=1900(1.035)^2\implies A=2035.3275


Brian invested the money for 6 years, so now let's check how much is that for the remaining 4 years.


\bf ~~~~~~ \textit{Compound Interest Earned Amount} \\\\ A=P\left(1+\frac{r}{n}\right)^{nt} \quad \begin{cases} A=\textit{accumulated amount}\\ P=\textit{original amount deposited}\dotfill &2035.3275\\ r=rate\to 4.9\%\to \frac{4.9}{100}\dotfill &0.049\\ n= \begin{array}{llll} \textit{times it compounds per year}\\ \textit{yearly, thus once} \end{array}\dotfill &1\\ t=years\dotfill &4 \end{cases}


\bf A=2035.3275\left(1+\frac{0.049}{1}\right)^{1\cdot 4}\implies A=2035.3275(1.049)^4 \\\\\\ A\approx 2464.54\implies \boxed{\stackrel{\textit{rounded up }}{A=2465}}

4 0
3 years ago
The year 2004 has the units digit equal to twice the thousands digit. How many years will it be before this next happens?
Valentin [98]

Step-by-step explanation:

the answer should be 1004

5 0
3 years ago
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