Best is to draw a sketch of the three points.
Next step is to find the distances BC, CD, DB.
The perimeter is the sum of the three distances.
The distances are found using the distance formula:
D=sqrt((y2-y1)^2+(x2-x1)^2)
order of (x1,y1), (x2,y2) is not important.
BC=sqrt((3- -3)^2+(5-3)^2)=sqrt(6^2+2^2)=sqrt(40)=5.324
CD=sqrt((-1-3)^2+(0-5)^2)=sqrt(4^2+5^2)=sqrt(41)=6.403
DB=sqrt((-3- -1)^2+(3-0)^2)=sqrt(2^2+3^2)=sqrt(13)=3.606
So perimeter = BC+CD+DB=16.333 (approximately)
Answer:
x = amount of real fruit juice used to make Drink A
y = amount of real fruit juice used to make Drink B
Step-by-step explanation:
Let
x = amount of real fruit juice used to make Drink A
y = amount of real fruit juice used to make Drink B
1. The company used 100.5 liters of real fruit juice, then
2. Drink A:
x = amount of real fruit juice used
percentage of real fruit juice
Then
5x = amount of drink A produced
Drink B:
y = amount of real fruit juice used
percentage of real fruit juice
Then
amount of drink B produced
The company makes 30 more liters of Drink A than liters of Drink B, so
The system of two equations is
Answer:
1/15
Step-by-step explanation:
First you must figure out your total outcomes, int the problem it said ten. Than take the number of students and put the number of students over the number of outcomes. This will tell you the probability of drawing one student. Next you must subtract 1 student and one member from your original equation. This is because you have assumed that the first drawing had a favorable outcome. So that leaves you with 2/9. Next you must multiply both the first fraction (3/10) and the second fraction (2/9) to come up with the total probability of the event occurring.
Hope that helped.
Answer:
ZP=66
Step-by-step explanation:
Quadrilateral WXYZ is a rectangle. Diagonals WY and ZX intersect at P. If PY=3x−5 and WP=2x+11, find the value of ZP.
9514 1404 393
Answer:
a) -1 5/14
b) -1/3
c) -1 : 10
Step-by-step explanation:
a) 1/7 - 0,5·3 = 1/7 -3/2 = (1·2 -3·7)/(7·2) = -19/14 = -1 5/14
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b) (3/4 -0,25)·(-2/3) = (3/4 -1/4)·(-2/3) = (2/4)(-2/3) = (1/2)(-2/3) = (-1·2)/(2·3) = -1/3
__
c) (1 5/6 -1,2) : (-6 1/3) = (11/6 -6/5) : (-19/3) = (11·5 -6·6)/(6·5) : (-190/30)
= (19/30) : (-190/30) = -19 : 190 = -1 : 10
