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choli [55]
3 years ago
11

Suppose a sales manager wants to compare different sales promotions. He chooses 5 different promotions and samples 10 random sto

res for each different promotion. The F value is 3.4. Using JMP, find the correct p-value.
Mathematics
1 answer:
elixir [45]3 years ago
5 0

Answer:

The correct p-value is 0.106.

Step-by-step explanation:

The information provided is as follows:

  • The sales manager chooses 5 different promotions and samples 10 random stores for each different promotion.
  • The F value is 3.4.

The degrees of freedom are:

<em>k</em> - 1 = 5 - 1 = 4

<em>n</em> - <em>k</em> = 10 - 5 = 5

Compute the <em>p</em>-value using Excel as follows:

p-value=P(F_{(k-1,n-k)}>3.4)\\\\=P(F_{(4,5)}>3.4)\\\\=F.DIST.RT(3.4,4,5)\\\\=0.106

Thus, the correct p-value is 0.106.

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Solve the inequality 2x2 + 10x &lt; –8
BigorU [14]

Answer:

-4<x<-1

Step-by-step explanation:

To solve the problem, we divide the whole expression by 2:

2x^2 + 10x < –8 → x^2 + 5x < –4

→  x^2 + 5x + 4 < 0

Factorizing

→ (x+4)(x+1) < 0

The expression is ONLY negative when:

x>-4 and x<-1

Therefore, the solution is:

-4<x<-1

5 0
3 years ago
The radius of a circle is 7cm. Find the circumference of the circle. Use 22/7 for pi
finlep [7]

Answer:

Hi I'm learning the same thing and I just got it I think it's C=43.98cm

8 0
3 years ago
Which of the following figures has a pentagon as its base? A cube B pentagonal prism C triangular prism D rectangular prism
yan [13]

Answer:

Option B. Pentagonal prism

Step-by-step explanation:

Option (A). Cube

Base of a cube is a square.

Option (B). Pentagonal prism

A prism is always defined by its base.

Example: triangular prism, rectangular prism

Therefore, pentagonal prism will have a base in the shape of a pentagon.

Option (C). Triangular prism

Triangular prism will have a triangular base.

Option (D). Rectangular prism

Rectangular prism will have a rectangular base.

4 0
4 years ago
I need help and can u please show your work please and thank u
aivan3 [116]

Answer:

Ur mom lol she gave birth to a kid who knows nothin

Step-by-step explanation:

6 0
3 years ago
Consider rolling two fair dice one 3-sided the other 5-sided
Ne4ueva [31]

Since the dice are fair and the rolling are independent, each single outcome has probability 1/15. Every time we choose

1\leq x\leq 3,\quad 1\leq y \leq 5

We have P(X=x)=\frac{1}{3} and P(Y=y)=\frac{1}{5}, because the dice are fair.

Now we use the assumption of independence to claim that

P(X=x, Y=y) = P(X=x)\cdot P(Y=y) =\dfrac{1}{3}\cdot\dfrac{1}{5} = \dfrac{1}{15}

Now, we simply have to count in how many ways we can obtain every possible outcome for the sum. Consider the attached table: we can see that we can obtain:

  • 2 in a unique way (1+1)
  • 3 in two possible ways (1+2, 2+1)
  • 4 in three possible ways
  • 5 in three possible ways
  • 6 in three possible ways
  • 7 in two possible ways
  • 8 in a unique way

This implies that the probabilities of the outcomes of W=X+Y are the number of possible ways divided by 15: we can obtain 2 and 8 with probability 1/15, 3 and 7 with probability 2/15, and 4, 5 and 6 with probabilities 3/15=1/5

8 0
3 years ago
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