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butalik [34]
3 years ago
5

+

Mathematics
1 answer:
GalinKa [24]3 years ago
6 0

Answer:

36 votes

(2x7)-(3x1) Take each instruction separately, use brackets to separate their action  More

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A playground is shaped like a quaderaleteral with all sides 27 feet long, with two angles measures of 65 degrees and two angles
Ksivusya [100]

Answer:

Rhombus

Step-by-step explanation:

Shape of a playground is a quadrilateral

It is given that  all sides of a quadrilateral are= 27 feet

Since all the sides of a quadrilateral are equal that it can be either a rhombus or it can be a square

Two angle are 65° each

And other two angers are 115° each

65°+ 115°= 180°

It forms a co-interior angle

Hence the quadrilateral is a parallelogram

Since all the four sides of parallelogram are equal, than the given figure must be rhombus

Hence, geomatric shape best describes the shape of the playground is Rhombus.

7 0
3 years ago
Evaluate<br> 8a-b<br> if a = 10 and b= 6
solniwko [45]

Answer:

74

Step-by-step explanation:

(8x10) - 6 =

80 - 6 = 74

4 0
1 year ago
5. Is s = 8 a solution to the inequality below? a) s &lt; 2​
JulijaS [17]

Answer:

Step-by-step explanation:

no, as 8 is not <2

4 0
2 years ago
Let a be a rational number and b be an irrational number. Which of the following are true statements?(there is more than 1 answe
kramer
<span>A.) the sum of a and b is never rational.
This is a true statement. Since an irrational umber has a decimal part that is infinite and non-periodical, when you add a rational number to an irrational number, the result will have the same infinite non periodical decimal part, so the new number will be irrational as well.

</span><span>B.) The product of a and b is rational
This one is false. Zero is a rational number, and when you multiply an irrational number by zero, the result is always zero.

</span><span>C.) b^2 is sometimes rational
This one is true. When you square an irrational number that comes from a square root like </span>\sqrt{2}, you will end with a rational number: ( \sqrt{2} )^{2}=2, but, if you square rationals from different roots than square root like \sqrt[3]{2}, you will end with an irrational number: \sqrt[3]{2^{2} } = \sqrt[3]{2}. 

<span>D.) a^2 is always rational
This one is false. If you square a rational number, you will always end with another rational number.

</span><span>E.) square root of a is never rational
</span>This one is false. The square root of perfect squares are always rational numbers: \sqrt{64} =8, \sqrt{16} =4,...

F.) square root of b is never rational
This one is true. Since the square root of any non-perfect square number is irrational, and all the irrational numbers are non-perfect squares, the square root of an irrational number is always irrational.

We can conclude that given that<span> a is a rational number and b be an irrational number, A, C, D, and F are true statements.</span>
4 0
2 years ago
Reference attached image for the problem.Please show your work for finding the partial area.
-Dominant- [34]

To find the area of a sector of a circle use the next formula:

A=\frac{\theta}{360º}*\pi *r^2

As the given circle has a outside angle 90º (it is not part of the sector of the circle) subtract the 90º from 360º (total angle of a circle) to find the angle of the sector:

\theta=360º-90º=270º

Find the area of the sector with angle 270º:

\begin{gathered} A=\frac{270º}{360º}*3.14*(11in)\placeholder{⬚}^2 \\  \\ A=0.75*3.14*121in^2 \\  \\ A=284.955in^2 \end{gathered}Then, the approximate area of the given sector of a circle is 284.955 square inches
7 0
9 months ago
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