Answer:
49
Step-by-step explanation:
angle QPR and angle TPS are alternate angles and their measure is equal to each other:
3x + 1 = 148 subtract 1 from both sides
3x = 147 divide both sides by 3
x = 49
Answer:
<h2>m∠ACE = 90°</h2>
Step-by-step explanation:
Figure Interpretation:
m∠CBA + m∠CDE = 180
m∠BCA = (180-m∠CBA)/2
m∠DCE = (180-m∠CDE)/2
=======================
Then
m∠BCA + m∠DCE = (180-m∠CBA)/2 + (180-m∠CDE)/2
= [360-(m∠CBA+m∠CDE)]/2
= [360 - 180]/2
= 90
finally,
m∠ACE= 180 - (m∠BCA + m∠DCE)
= 180 - 90
= 90
D. right
a right angle always equals a right triangle
Use ac method
for ax²+bx+c=0 when a≠1
multiply a and c, let's call the product r
what 2 numbesr multiply to get r and add to get b
2y²+9y+9=0
2*9=18
wat 2 numbers multiply to get 18 and add to get 9
3 and 6
split it up to that
2y²+3y+6y+9=0
group
(2y²+3y)+(6y+9)=0
factor
y(2y+3)+3(2y+3)=0
undistribute
(y+3)(2y+3)=0
set to zero
y+3=0
y=-3
2y+3=0
2y=-3
y=-3/2
y=-3 and -3/2
it's factored form is (x+3)(2x+3)
A) 3.3 m/s
1 km/ 5 minutes
=1000 m/ 5(60) s
= 1000 m/ 300s
=10/3 s
=3.3 m/s
