The soda water didn't freeze because of the depression in freezing point as compared to the water.
<h3>What is Freezing Point Depression ?</h3>
When a solute is added to a pure solvent , then the value of freezing point is reduced.
The decrease in the freezing point is directly proportional to the molality of the solute.
It is given in the question that
A student put a bottle of water and a can of sugared soda in the freezer to chill them quickly.
when she took them out, the bottle of water was frozen but the can of soda was not.
It is because water is the pure solvent , so freezing point is fixed but the soda water has sugar and Carbon Di oxide along with the solvent water , the presence of the sugar and Carbon -di-oxide decreases the freezing point of the soda water and so it doesn't freezes.
To know more about Freezing Point Depression
brainly.com/question/2292439
#SPJ1
5 ml=5 cm³ , density=mass/volume=45/5= 9 g/cm³ therefore answer B
The pressure exerted by 0.57 moles of CO2 at a temperature of 25°C and a volume of 500 ml is 28 atm.
<u>Explanation:</u>
According to ideal gas law,
PV = nRT
where P represents the pressure of a gas,
V represents the volume of a gas,
n represents the number of moles,
R represents the gas constant = 0.0821 L atm / mol K.
T represents the temperature of a gas.
Given V = 500 ml = 0.5 l, T = 25°C = 298 K, n = 0.57 mol
PV = nRT
P = nRT / V
= (0.57 
0.0821 298) / 0.5
P = 28 atm.
The pressure of a gas is 28 atm.
Answer:
neither accurate nor precise
Explanation:
Accuracy is the ability to give the same result on different measurements made under the same conditions or to give the desired result accurately, therefore, as observed in the image, the results are not accurate, since they are all different.
They are not precise either, since the precision is the degree of agreement between the independent results of a measurement, obtained under stipulated conditions, be it repeatability, reproducibility or intermediate.
