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ella [17]
3 years ago
15

What pressure will be exerted by 0.57 moles of CO2 at a temperature of 25°C and a volume of 500 ML? _____atm

Chemistry
1 answer:
svetlana [45]3 years ago
4 0

The pressure exerted by 0.57 moles of CO2 at a temperature of 25°C and a volume of 500 ml is 28 atm.

<u>Explanation:</u>

According to ideal gas law,

                                      PV = nRT

where P represents the pressure of a gas,

          V  represents the volume of a gas,

          n represents the number of moles,

          R represents the gas constant = 0.0821 L atm / mol K.

          T represents the temperature of a gas.

Given V = 500 ml = 0.5 l,           T = 25°C = 298 K,   n = 0.57 mol

                                        PV = nRT

                                           P = nRT / V

                                              = (0.57 \times 0.0821 \times 298) / 0.5

                                          P = 28 atm.

The pressure of a gas is 28 atm.

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What is the molar mass of an unknown gas<br> with a density of 4.95 g/L at 1.00 atm and<br> 25.0 °C?
mestny [16]

Answer:

121 g/mol

Explanation:

To find the molar mass, you first need to calculate the number of moles. For this, you need to use the Ideal Gas Law. The equation looks like this:

PV = nRT

In this equation,

-----> P = pressure (atm)

-----> V = volume (L)

-----> n = moles

-----> R = constant (0.0821 L*atm/mol*K)

-----> T = temperature (K)

Because density is comparing the mass per 1 liter, I am assuming that the system has a volume of 1 L. Before you can plug the given values into the equation, you first need to convert Celsius to Kelvin.

P = 1.00 atm                         R = 0.0821 L*atm/mol*K

V = 1.00 L                             T = 25.0. °C + 273.15 = 298.15 K

n = ? moles

PV = nRT

(1.00 atm)(1.00L) = n(0.0821 L*atm/mol*K)(298.15 K)

1.00 = n(0.0821 L*atm/mol*K)(298.15 K)

1.00 = (24.478115)n

0.0409 = n

Now, we need to find the molar mass using the number of moles per liter (calculated) and the density.

0.0409 moles           ? grams           4.95 grams
----------------------  x  ------------------  =   ------------------
        1 L                       1 mole                     1 L

? g/mol = 121 g/mol

**note: I am not 100% confident on this answer

3 0
2 years ago
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