The mass of a length of metal wire is 45 g. When the wire is placed in a graduated

Chemistry

2 answers:

Fofino [41]4 years ago

8 0

Answer:

The answer to your question is 9 g/ml or 9 g/cm³

Explanation:

Data

mass = 45 g

volume = 5 ml

density = ?

Process

1.- Consider that the volume displaced is equal to the volume of the wire.

2.- Write the formula to calculate the density

density = mass/volume

3.- Substitution

density = 45/5

consider milliliters and cubic centimeters are the same.

4.- Result

density = 9 g/ml or 9 g/cm³

babunello [35]4 years ago

7 0

5 ml=5 cm³ , density=mass/volume=45/5= 9 g/cm³ therefore answer B

You might be interested in

This graph shows the solution to the inequality y > 3x + 14 and y < 3x + 2

erik [133]

For apex the answer is no solution

7 0

3 years ago

Why is the equation 4Al+302>2Al203 balanced

cestrela7 [59]

Answer:

It's coefficient to the front of each element that requires it.

Explanation:

It is coefficient to the front of each element or compound that requires it. Essentially you are multiplying the amount of atoms or compounds on one side to match the amount on the other side.

8 0

3 years ago

What did the immigration act of 1965 do?

storchak [24]

Changed the way quotas were allocated by ending the National Origins Formula that had been in place in the United States since the Emergency Quota Act<span> of 1921.</span>

7 0

3 years ago

Which part of the atom is so small it contributes very little to the mass of an atom

sasho [114]

My part of the atom, I'm guessing you are referring to the protons, neutrons, and electrons.

The smallest of these three is the electron.

8 0

4 years ago

Write the following in scientific notation. Include the unit or it will be marked wrong. a. 3450 meters b. 0.0000432 liters c. 5

Anvisha [2.4K]

Answer:

$a. \: 3.450 \: \times \: {10}^{3} \: m \\ \\ b. \: 4.32 \: \: \times \: {10}^{ - 5} \: l \\ \\ c. \: 5.06 \: \times \: {10}^{5} {cm}^{3}$