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spayn [35]
3 years ago
5

2. Peter's mom wrote down the number of items purchased every week at the grocery store as well

Mathematics
2 answers:
Vilka [71]3 years ago
7 0

Answer:

A

Step-by-step explanation:

balu736 [363]3 years ago
4 0

Answer:

Step-by-step explanation:

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Please HELP ME omg istggg plsss im begging yalll
Pie
The answer is b I did this test yesterday
5 0
3 years ago
Factor: 10x^3-35x^2-12x+42<br><br> I'll give brainliest :) but please show all work.
alexandr402 [8]

Answer:

\left(2x-7\right)\left(5x^2-6\right)

Explanation:

\hookrightarrow\sf 10x^3-35x^2-12x+42

using associative property, separate

\hookrightarrow\sf \left(10x^3-35x^2\right)+\left(-12x+42\right)

take common term, factorise

\hookrightarrow\sf 5x^2\left(2x-7\right)-6\left(2x-7\right)

final answer

\hookrightarrow\sf \left(2x-7\right)\left(5x^2-6\right)

5 0
2 years ago
Read 2 more answers
Hey! Please help me with this kahn question<br> thanks!
Alekssandra [29.7K]

Answer:

z^{11}

Step-by-step explanation:

add 5 and 6 because they have the same base z

4 0
3 years ago
Evaluate 8x + 7 given that x - 3 = 10
Marta_Voda [28]

First find what x is equal to

x - 3 = 10

add 3

x = 13

Plug 13 for x

8 * 13 + 7 = 111
4 0
3 years ago
Find the value of x² - x+1 when x=√3 -1, in the form a+b√3 where a and b are integers​
lidiya [134]

Answer:

6-3\sqrt{3}

If you compare this to a+b\sqrt{3}, then a=6 and b=-3.

Step-by-step explanation:

We are given x=\sqrt{3}-1 and we are asked to find the value of x^2-x+1.

So we will need to find x^2.

x=\sqrt{3}-1

Square both sides:

x^2=(\sqrt{3}-1)^2

Expand using identity: (x-a)^2=x^2-2ax+a^2.

x^2=(\sqrt{3})^2-2(\sqrt{3})(1)+1^2

x^2=3-2\sqrt{3}+1

x^2=4-2\sqrt{3}

Let's go back to the full x^2-x+1.

x^2-x+1

(4-2\sqrt{3})-(\sqrt{3}-1)+1

4-2\sqrt{3}-\sqrt{3}+1+1

6-3\sqrt{3}

If you compare this to a+b\sqrt{3}, then a=6 and b=-3.

5 0
4 years ago
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