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3 years ago

5

2. Peter's mom wrote down the number of items purchased every week at the grocery store as well

2 answers:

Vilka [71]3 years ago

7 0

Answer:

A

Step-by-step explanation:

balu736 [363]3 years ago

4 0

Answer:

Step-by-step explanation:

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Please HELP ME omg istggg plsss im begging yalll

Pie

The answer is b I did this test yesterday

5 0

3 years ago

Factor: 10x^3-35x^2-12x+42<br><br> I'll give brainliest :) but please show all work.

alexandr402 [8]

Answer:

$\left(2x-7\right)\left(5x^2-6\right)$

Explanation:

$\hookrightarrow\sf 10x^3-35x^2-12x+42$

using associative property, separate

$\hookrightarrow\sf \left(10x^3-35x^2\right)+\left(-12x+42\right)$

take common term, factorise

$\hookrightarrow\sf 5x^2\left(2x-7\right)-6\left(2x-7\right)$

final answer

$\hookrightarrow\sf \left(2x-7\right)\left(5x^2-6\right)$

5 0

2 years ago

Read 2 more answers

Hey! Please help me with this kahn question<br> thanks!

Alekssandra [29.7K]

Answer:

$z^{11}$

Step-by-step explanation:

add 5 and 6 because they have the same base z

4 0

3 years ago

Evaluate 8x + 7 given that x - 3 = 10

Marta_Voda [28]

First find what x is equal to

x - 3 = 10

add 3

x = 13

Plug 13 for x

8 * 13 + 7 = 111

4 0

3 years ago

Find the value of x² - x+1 when x=√3 -1, in the form a+b√3 where a and b are integers

lidiya [134]

Answer:

$6-3\sqrt{3}$

If you compare this to $a+b\sqrt{3}$ , then $a=6$ and $b=-3$ .

Step-by-step explanation:

We are given $x=\sqrt{3}-1$ and we are asked to find the value of $x^2-x+1$ .

So we will need to find $x^2$ .

$x=\sqrt{3}-1$

Square both sides:

$x^2=(\sqrt{3}-1)^2$

Expand using identity: $(x-a)^2=x^2-2ax+a^2$ .

$x^2=(\sqrt{3})^2-2(\sqrt{3})(1)+1^2$

$x^2=3-2\sqrt{3}+1$

$x^2=4-2\sqrt{3}$

Let's go back to the full $x^2-x+1$ .

$x^2-x+1$

$(4-2\sqrt{3})-(\sqrt{3}-1)+1$

$4-2\sqrt{3}-\sqrt{3}+1+1$

$6-3\sqrt{3}$

If you compare this to $a+b\sqrt{3}$ , then $a=6$ and $b=-3$ .

5 0

4 years ago