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3 years ago

Choose the quadratic equation with a leading coefficient of 6 and solutions 5 and -2/3

Mathematics

1 answer:

Paha777 [63]3 years ago

5 0

Answer:

Option D

Step-by-step explanation:

Verify each quadratic equation

case A) we have

This quadratic equation has a leading coefficient of 1

Substitute the value of x=3 and x=-2 in the equation

For x=3

----> is not true

therefore

x=3 is not a solution of the quadratic equation

case B) we have

This quadratic equation has a leading coefficient of 1

Substitute the value of x=3 and x=-2 in the equation

For x=3

----> is not true

therefore

x=3 is not a solution of the quadratic equation

case C) we have

This quadratic equation has a leading coefficient of 1

Substitute the value of x=3 and x=-2 in the equation

For x=3

----> is not true

therefore

x=3 is not a solution of the quadratic equation

case D) we have

This quadratic equation has a leading coefficient of 1

Substitute the value of x=3 and x=-2 in the equation

For x=3

----> is true

therefore

x=3 is a solution of the quadratic equation

For x=-2

----> is true

therefore

x=-2 is a solution of the quadratic equation

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Answer:

x = 2

Step-by-step explanation:

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$8x-7=2x+5\\6x-7=5\\6x=12\\x=2$

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2 years ago

Sarah kicked a ball in the air. The function

Aleksandr-060686 [28]

Answer: The ball hits the ground at 5 s

Step-by-step explanation:

The question seems incomplete and there is not enough data. However, we can work with the following function to understand this problem:

$f=30 t- 6t^{2}$ (1)

Where $f$ models the height of the ball in meters and $t$ the time.

Now, let's find the time $t$ when the ball Sara kicked hits the ground (this is when $f=0 m$ ):

$0=30 t- 6t^{2}$ (2)

Rearranging the equation:

$6t^{2}-30 t=0$ (3)

Dividing both sides of the equation by $6$ :

$t^{2}-5 t=0$ (4)

This quadratic equation can be written in the form $at^{2}+bt+c=0$ , and can be solved with the following formula:

$t=\frac{-b \pm \sqrt{b^{2}-4ac}}{2a}$ (5)

Where:

$a=1$

$b=-5$

$c=0$

Substituting the known values:

$t=\frac{-(-5) \pm \sqrt{(-5)^{2}-4(1)(0)}}{2(1)}$ (6)

Solving we have the following result:

$t=5 s$ This means the ball hit the ground 5 seconds after it was kicked by Sara.

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3 years ago

Find the missing coordinate to complete the ordered-pair solution to the given linear equation.

ad-work [718]

Y=7x+1

*note that the first number is always the x.
so,

a) (0,?)
y=7(0)+1
y=1
(0,1)

b) (3,?)
y=7(3)+1
y=21+1
y=22
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6 0

3 years ago

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What is the approximate value of X? Round to the nearest tenth.

pychu [463]

Answer

Find out the value of x.

To prove

By using the trignometric identity

$sin\theta = \frac{Perpendicular}{Hypotenuse}$

As given in the diagram.

$\theta = 50 ^{\circ}$

Perpendicular = x

Hypotenuse = 6

Put in the above identity

$sin\ 50^{\circ} = \frac{x}{6}$

$sin\ 50^{\circ} = 0.77\ (Approx)$

Put in the above

$x = 6\times 0.77$

x = 4.6 cm (Approx)

Therefore Option (c) is correct .

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Fofino [41]

Answer:

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Step-by-step explanation:

because we have 15 dark chocolates and 25 milk chocolate

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