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alexira [117]
3 years ago
6

Solve to find the value for x in the linear equation: 3(−4x + 5) = 12.1. Use the distributive property: 2. Use the subtraction p

roperty of equality:3. Division property of equality: 3(−4x) + 3(5) = 12−12x + 15 = 12−12x + 15 − 15 = 12 − 15−12x = −3 x =
Mathematics
2 answers:
pogonyaev3 years ago
9 0

Answer:

1/4

Step-by-step explanation:

Take my word for it.

(Yes I know this answer is late)

Brrunno [24]3 years ago
5 0

Answer:

x =\frac{7}{12}

Step-by-step explanation:

Given equation,

3(-4x + 5) = 12

Step 1 : Using distributive of equality,

3(-4x) + 3(5) = 12

Step 2 : simplify,

-12x + 15 = 12

Step 3 : Using subtraction property of equality,

-12x = 12 - 15

Step 4 : Simplify,

-12x = -7

Step 5 : Using division property of equality,

x =\frac{7}{12}

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anwser is a

Step-by-step explanation:

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3 years ago
Which equation could be used to solve for the value of n if n + 2 = 6?
NNADVOKAT [17]

You can use 6-2=4

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5 0
3 years ago
An automobile manufacturer obtains the microprocessors used to regulate fuel consumption in its automobiles from three microelec
Anastaziya [24]

Answer:

The probability that a randomly selected automobile manufactured by the company will have a defective microprocessor is 6.2 %.

Step-by-step explanation:

Given:

The probability of getting a microprocessor from firm A is, P(A)=45\%=0.45

The probability of getting a microprocessor from firm B is, P(B)=30\%=0.30

The probability of getting a microprocessor from firm C is, P(C)=25\%=0.25

Now, let event D be having a defective microprocessor at random.

So, as per the question,

Probability of producing a defective microprocessor from firm A is, P(D/A)=6\%=0.06

Probability of producing a defective microprocessor from firm B is, P(D/B)=7\%=0.07

Probability of producing a defective microprocessor from firm C is, P(D/C)=5.5\%=0.055

Now, probability of having a defective microprocessor when selected at random is given as:

P(D)=P(A)\cdot P(D/A)+P(B)\cdot P(D/B)+P(C)\cdot P(D/C)\\P(D)=(0.45\times 0.06)+(0.30\times 0.07)+(0.25\times 0.055)\\P(D)=0.027+0.021+0.01375\\P(D)=0.06175\ or\ P(D)=0.06175\times 100\approx 6.2\%

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5 0
3 years ago
What experimental of rolling a 2 or 3
kondor19780726 [428]

Answer:

Option 1: 0.32

Step-by-step explanation:

Let

P(A) be the experimental probability of getting two

And

P(B) be the experimental probability of getting three

The dice is rolled 360 times.

So the sample space is n(S) = 360

P(A) = n(A)/n(S)

= 54/360

= 0.15

And

P(B) = n(B)/n(S)

= 62/360

= 0.172

As both the events A and B are mutually exclusive,

P(A or B)  = P(A) + P(B)

= 0.15 + 0.172

=0.322

Rounding of to one decimal gives us:

0.32

So the probability of rolling a two or three is 0.32 ..

3 0
3 years ago
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liraira [26]

The sum of 2 complementary angles equals 90 degrees.


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The answer would be true.

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