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Annette [7]
3 years ago
11

PLS ANSWER PHOTO ATTACHED

Mathematics
2 answers:
Snezhnost [94]3 years ago
7 0
The answer would be 12
AURORKA [14]3 years ago
4 0

Answer:

its 12

Step-by-step explanation:

You might be interested in
Clara lends half her collection of formal attires to her sister, Susan. Clara then buys
Digiron [165]

Answer:

clara had 16 but she gave half that leaves us with 8 + 4 gives u 12

x

2

+ 4 = 12 ; 16 attires  

Answer:

16

Step-by-step explanation:

a:2+4 =12

a:2=12-4

a:2=8

a=8 ×2

a=16 dresses

Step-by-step explanation:

brainliest would be super appreciated

5 0
3 years ago
Find the area of a parallelogram that is 10 m long has a height of 4 m and a width of 5 m
alukav5142 [94]
You would take the base and multiply it by the height. So you would take 10x4 and that would give you 40
8 0
3 years ago
Help me please!!!!!!!!!!!!!!
tia_tia [17]

Answer:

okay so you would make a line straight across the middle of the spherical shape. The line that goes all the way across is the diameter. If you were to cut that line in half that would be the radius.

Step-by-step explanation:

The first circle shown in the picture provided would be an example of diameter, and the second circle would be an example of the radius. You could just make up a value, for example say the diameter is 10, the radius would be 5.

5 0
3 years ago
On a coordinate plane, 2 triangles are shown. The first triangle has points A (1, 4), B (3, 4), C (3, 2). The second triangle ha
cluponka [151]

Answer:

B, E

Step-by-step explanation:

7 0
3 years ago
Read 2 more answers
Consider the planes 4x+3y+4z=1 and 4x+4z=0. (A) Find the unique point P on the y−axis which is on both planes. ( 0 equation edit
Nana76 [90]

Answer:

Step-by-step explanation:

A) From the order of the exercise we already know that the intersection points lies on the Y-axis, so its coordinates are P(0;y;0). In order to find it, we only need to substitute the equation 4x+4z=0 into the equation 4x+3y+4z=1. Then,

1=4x+3y+4z = 3y + (4x+4z)= 3y+0.

From the expression above it is easy to obtain that y=1/3, and the intersection point is P(0;1/3;0).

B) To obtain the parallel vector to both planes we use the cross product of the normal vector of the planes.

\left[\begin{array}{ccc}i&j&k\\4&3&4\\4&0&4\end{array}\right] = 12i-0j+12k

As we want a unit vector, we must calculate the modulus of u:

|u|=\sqrt{12^2+0^2+12^2} = \sqrt{2\cdot 12^2}=12\sqrt{2}.

Thus, the wanted vector is \frac{u}{12\sqrt{2}}. Therefore,

u = \frac{1}{\sqrt{2}}i-\frac{1}{\sqrt{2}}k = \frac{\sqrt{2}}{2}i-\frac{\sqrt{2}}{2}k.

C) In order to obtain the vector equation of the intersection line of both planes, we just need to put together the above results.

r = \frac{1}{3}j +\lambda \left( \frac{\sqrt{2}}{2}i- \frac{\sqrt{2}}{2}k \right)

where \lambda is a real number.

8 0
4 years ago
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