Question

Lugi is trying to hit a turtle shell. The height of

Answer 1

Answer:

C. 6.02sec

Step-by-step explanation:

Given

$h(t) = -16t\² +96t + 2$

Required

Time to hit the ground

When the turtle shell hits the ground, $h(t) = 0$

So:

$0 = -16t\² +96t + 2.$

Solving using quadratic formula:

$t = \frac{-b\±\sqrt{b^2-fac}}{2a}$

Where:

$a = -16; b =96; c = 2$

So:

$t = \frac{-96\±\sqrt{96^2-4 * -16 * 2}}{2*-16}$

$t = \frac{-96\±\sqrt{9344}}{-32}$

$t = \frac{-96\±96.66}{-32}$

Split:

$t = \frac{-96+96.66}{-32}$ or $t = \frac{-96-96.66}{-32}$

$t = \frac{0.66}{-32}$ or  $t = \frac{-192.66}{-32}$

$t = -0.020625$ or  $t = 6.020625$

So time can't be negative, we have:

$t = 6.020625$

Option C answers the question