Since in a pass code, the placement of the digits is
important, therefore this means that to solve for the total number of
possibilities we have to make use of the principle of Permutation. The formula
for calculating the total number of possibilities using Permutation is given
as:
P = n! / (n – r)!
where,
n = is the total amount of numbers to choose from = 20
r = is the total number of digits needed in the passcode =
4
Therefore solving for the total possibilities P:
P = 20! / (20 – 4)!
P = 20! / 16!
P = 116,280
<span>Hence there are a total of 116,280 possibilities of pass
codes.</span>
Answer:
-1.9
Step-by-step explanation:
He has $1.10 in his printing account. 0.25 each sheet of paper.
47 pages.
He printed both sides so 47:2= 23.5.
Because he printed 2 pages then we divide by 2.
23.5:2=11.75
We cannot print a half of page, so we print 12 pages.
12*0.25=3
1.10-3=-1,9
His printing account will be in minus.
With the given table, this isn't possible without resorting to an approximation of an approximation.
The interval
![[0,8]](https://tex.z-dn.net/?f=%5B0%2C8%5D)
can be partitioned as
![[0,2]\cup[2,4]\cup[4,6]\cup[6,8]](https://tex.z-dn.net/?f=%5B0%2C2%5D%5Ccup%5B2%2C4%5D%5Ccup%5B4%2C6%5D%5Ccup%5B6%2C8%5D)
, with the respective midpoints of

. So the average temperature is given exactly by the definite integral

which is approximated by

where the coefficient

comes from the fact that each subinterval has length 2, and so

.
However, you don't know the values of

at these points. At best you can approximate them, perhaps by interpolating

(you have the details needed to do it, at any rate).
Are you sure you're not supposed to find the average temperature over the entire set of observation times, i.e. over

?
To find this you have to divide 351 by 46, which is <span>7.63043478261 but you can round it to 8. So it would be 8.</span>
4000(1.5)x = 25,000
25000/4000 = 1.5x
6.25 = 1.5x
25/6 = x