1answer.
Ask question
Login Signup
Ask question
All categories
  • English
  • Mathematics
  • Social Studies
  • Business
  • History
  • Health
  • Geography
  • Biology
  • Physics
  • Chemistry
  • Computers and Technology
  • Arts
  • World Languages
  • Spanish
  • French
  • German
  • Advanced Placement (AP)
  • SAT
  • Medicine
  • Law
  • Engineering
oksano4ka [1.4K]
3 years ago
9

Jada has a scale map of kansas that fits on a page in her book. The page is 5 inches by 8 inches. Kansas is about 210 miles by 4

10 miles. Select all scales that could be a scale on the map. (There are 2.54 centimeters in an inch.)
A. 1 in to 1 my
B. 1 cm to 1 km
C. 1 in to 10 mi
D. 1 ft to 100 mi
E. 1 cm to 200 km
F. 1 in to 100 mi
G. 1 cm to 1000 km
Mathematics
2 answers:
malfutka [58]3 years ago
7 0

Answer:

E. 1 cm to 200 Km

F. 1 in to 100 mi

G. 1 cm to 1,000 Km

Step-by-step explanation:

Verify each case

case A) 1 in to 1 mi

In this part the scale is equal to

\frac{1}{1}\frac{in}{mi}

Convert the actual dimensions of Kansas to the model dimensions on a map and compare with the dimensions of the page of the book

By proportion

\frac{1}{1}\frac{in}{mi}=\frac{x}{210}\frac{in}{mi}\\ \\x=210\ in

\frac{1}{1}\frac{in}{mi}=\frac{x}{410}\frac{in}{mi}\\ \\x=410\ in

The dimensions of Kansas on a map is greater than the dimensions of the page

therefore

case A) is not the solution

case B) 1 cm to 1 Km

In this part the scale is equal to

\frac{1}{1}\frac{cm}{Km}

Convert the dimensions of the book to cm

1\ in=2.54\ cm

so

5\ in=5*2.54=12.70\ cm

8\ in=8*2.54=20.32\ cm

Convert the actual dimensions of Kansas to Km

1\ mi=1.609344\ Km

so

210\ mi=210*1.609344=337.96\ Km

410\ mi=410*1.609344=659.83\ Km

Convert the actual dimensions of Kansas to the model dimensions on a map and compare with the dimensions of the page of the book

By proportion

\frac{1}{1}\frac{cm}{km}=\frac{x}{337.96}\frac{cm}{km}\\ \\x=337.96\ cm

\frac{1}{1}\frac{cm}{km}=\frac{x}{659.83}\frac{cm}{km}\\ \\x=659.83\ cm

The dimensions of Kansas on a map is greater than the dimensions of the page

therefore

case B) is not the solution

case C) 1 in to 10 mi  

In this part the scale is equal to

\frac{1}{10}\frac{in}{mi}

Convert the actual dimensions of Kansas to the model dimensions on a map and compare with the dimensions of the page of the book

By proportion

\frac{1}{10}\frac{in}{mi}=\frac{x}{210}\frac{in}{mi}\\ \\x=210/10=21\ in

\frac{1}{10}\frac{in}{mi}=\frac{x}{410}\frac{in}{mi}\\ \\x=410/10=41\ in

The dimensions of Kansas on a map is greater than the dimensions of the page

therefore

case C) is not the solution

case D) 1 ft to 100 mi

In this part the scale is equal to

\frac{1}{100}\frac{ft}{mi}

Convert the dimensions of the book to ft

1\ ft=12\ in

so

5\ in=5/12=0.42\ ft

8\ in=8/12=0.67\ ft

Convert the actual dimensions of Kansas to the model dimensions on a map and compare with the dimensions of the page of the book

By proportion

\frac{1}{100}\frac{ft}{mi}=\frac{x}{210}\frac{ft}{mi}\\ \\x=210/100=2.1\ ft

\frac{1}{100}\frac{ft}{mi}=\frac{x}{410}\frac{ft}{mi}\\ \\x=410/100=4.1\ ft

The dimensions of Kansas on a map is greater than the dimensions of the page

therefore

case D) is not the solution

case E) 1 cm to 200 Km

In this part the scale is equal to

\frac{1}{200}\frac{cm}{Km}

Convert the dimensions of the book to cm

1\ in=2.54\ cm

so

5\ in=5*2.54=12.70\ cm

8\ in=8*2.54=20.32\ cm

Convert the actual dimensions of Kansas to Km

1\ mi=1.609344\ Km

so

210\ mi=210*1.609344=337.96\ Km

410\ mi=410*1.609344=659.83\ Km

Convert the actual dimensions of Kansas to the model dimensions on a map and compare with the dimensions of the page of the book

By proportion

\frac{1}{200}\frac{cm}{km}=\frac{x}{337.96}\frac{cm}{km}\\ \\x=337.96/200=1.69\ cm

\frac{1}{200}\frac{cm}{km}=\frac{x}{659.83}\frac{cm}{km}\\ \\x=659.83/200=3.30\ cm

The dimensions of Kansas on a map is less than the dimensions of the page

therefore  

case E) could be a scale on the map

case F) 1 in to 100 mi

In this part the scale is equal to

\frac{1}{100}\frac{in}{mi}

Convert the actual dimensions of Kansas to the model dimensions on a map and compare with the dimensions of the page of the book

By proportion

\frac{1}{100}\frac{in}{mi}=\frac{x}{210}\frac{in}{mi}\\ \\x=210/100=2.1\ in

\frac{1}{100}\frac{in}{mi}=\frac{x}{410}\frac{in}{mi}\\ \\x=410/100=4.1\ in

The dimensions of Kansas on a map is less than the dimensions of the page

therefore

case F) could be a scale on the map

case G) 1 cm to 1,000 Km

In this part the scale is equal to

\frac{1}{1,000}\frac{cm}{Km}

Convert the dimensions of the book to cm

1\ in=2.54\ cm

so

5\ in=5*2.54=12.70\ cm

8\ in=8*2.54=20.32\ cm

Convert the actual dimensions of Kansas to Km

1\ mi=1.609344\ Km

so

210\ mi=210*1.609344=337.96\ Km

410\ mi=410*1.609344=659.83\ Km

Convert the actual dimensions of Kansas to the model dimensions on a map and compare with the dimensions of the page of the book

By proportion

\frac{1}{1,000}\frac{cm}{km}=\frac{x}{337.96}\frac{cm}{km}\\ \\x=337.96/1,000=0.34\ cm

\frac{1}{1,000}\frac{cm}{km}=\frac{x}{659.83}\frac{cm}{km}\\ \\x=659.83/1,000=0.66\ cm

The dimensions of Kansas on a map is less than the dimensions of the page

therefore

case G) could be a scale on the map

Semenov [28]3 years ago
3 0
I think the letter is b
You might be interested in
9α – 8α<br><br> Can someone please answer this question ty
Andrei [34K]
1a (you don’t necessarily need to include the 1, so you can just put “a” if you’d like).
5 0
1 year ago
How do I solve: 3w/x=6e
lana [24]
The answer is ×=w/2e.thats it
7 0
3 years ago
#3 is what I need help on
miv72 [106K]

Answer: 11.05

Step-by-step explanation:

Divide 5.20 by 8 to find the price of each bag (which is .65 cents.) Multiple .65 by 20 (13). 15% of 13 is 1.95. 13 - 1.95 is 11.05

PS: 1.95 is the discount. Hope this helps. Have a good day.

3 0
2 years ago
Read 2 more answers
Use the distributive to find the price of 4 CDs that cost 14.99 each
Eva8 [605]
59.96. 

If you distribute 4 to 14.99 then you get the answer above. 
4 0
3 years ago
Will an object with a density of. 97 g/ml float or sink in water explain
Ainat [17]
I would say the object will float because the density of water is 999.99kg/m which is slightly less than 1g but still more than the object.
3 0
3 years ago
Other questions:
  • good job on increasing our team sales from 90 to 130 units per day.” wow i never thought that we could increase our sales by
    7·1 answer
  • Compute the flux H F of F(x,y) = hxy, x − yi across the boundary of the square given by −1 ≤ x ≤ 1, −1 ≤ y ≤ 1.
    5·1 answer
  • Which angles are alternate interior angles?
    8·2 answers
  • What is the equation of the line through (-1, -4) and parallel to the line 3x + y=5
    10·1 answer
  • Alycia created a personal budget for the upcoming month. She received a salary of $2,700 and had various fixed and variable expe
    13·1 answer
  • What is the solution of 3x + 5 = 2x - 7?
    11·1 answer
  • Submit
    7·1 answer
  • I need the answer, help me please
    14·2 answers
  • 2x +4&gt;- 6 and 5x -12&lt;3<br>​
    15·1 answer
  • Daniel got 75 marks,72 marks and 63 marks in three tests what is his average
    9·2 answers
Add answer
Login
Not registered? Fast signup
Signup
Login Signup
Ask question!