If h=5, then 6h-4 equals<br>

$1) \: \: \frac{5x}{2y} \\ a) \: \: x = 8 \: \: and \: \: y = 10 \\ \frac{5x}{2y} \\ \frac{5(8)}{2(10)} \\ \frac{40}{20} \\ 2 \: ans \\ b) \: \: \frac{5x}{2y} \\ \frac{5( \frac{1}{2}) }{2( \frac{2}{3}) } \\ \frac{2.5}{1.3} \\ \frac{25}{13} \\ 1.92 \: \: ans \: \\ \\ 2) \: \: \frac{a {b}^{3} }{c} \\ \\ a) \: \: a = 4 \: .\: b = 3 \: . \: c = 2 \\ \\ \frac{a {b}^{3} }{c} \\ \frac{(4) {(3)}^{3} }{2} \\ \frac{4(27)}{2} \\ \frac{108}{2} \\ 54 \: \: ans \: \\ \\ b) \: \: a = - 2 \: . \: b = - 2 \: . \: c = 2 \\ \\ \frac{a {b}^{3} }{c} \\ \frac{( - 2) {( - 2)}^{3} }{2} \\ \frac{ - 2 { (- 2)}^{3} }{2} \\ \frac{ - 2( - 8)}{2} \\ \frac{16}{2} \\ 8 \: \: ans \:$

Step-by-step explanation:

question 3 is already answered by me in your question..or you can see attachment.

3 0

2 years ago

Find the area of the quadrilateral

vodomira [7]

Answer:

The formula for a quadrilateral depends on the shape.

Area of a Parallelogram: Base × Height

Area of a Rectangle: Length × Breadth

Area of a Square: (side)^2

Area of a Kite: (1 ⁄ 2) × Product of Diagonals

Area of a Trapezoid: (base1+base2/2) x Height

I hope this helps :)

8 0

3 years ago

In a sample of 88 adults selected randomly from one town, it is found that 6 of them have been exposed to a particular strain of

Ivan

<h2>Answer with explanation:</h2>

Let p be the proportion of of all adults in the town that have been exposed to this strain of the flue .

As per given , we have

$H_0:p=0.08\\\\ H_a: p\neq0.08$

∵ $H_a$ is two-tailed , so the test is a two-tailed test.

Test statistic :

$z=\dfrac{\hat{p}-p}{\sqrt{\dfrac{p(1-p)}{n}}}$

, where p= population proportion

${\hat{p}$ = sample proportion

n= sample size

Put n= 6 and ${\hat{p}=\dfrac{6}{88}\approx0.068$ and p=0.08

$z=\dfrac{0.068-0.08}{\sqrt{\dfrac{0.08(1-0.08)}{88}}}$

$z=\dfrac{-0.012}{0.0289199522192}\approx-0.415$

P-value for two-tailed test : 2P(Z>|z|)

=2P(Z>|-0.415|)

=2P(Z>0.415)

=2[1-P(Z≤0.415)] [∵ P(Z>z)=1-P(Z≤z)]

=2(1-0.6609) [ by z-table]

=0.6782

Decision : Since the p-value(0.6782) is > significance level(0.01) , so we fail to reject the null hypothesis.

We conclude that that we do not have sufficient evidence to support the claim that the proportion of all adults in the town that have been exposed to this strain of the flue differs from the nationwide percentage of 8%.

8 0

3 years ago

If h=5, then 6h-4 equals​

If h=5, then 6h-4 equals