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suter [353]
3 years ago
5

Which scenario is best represented by a linear function?

Mathematics
1 answer:
nadezda [96]3 years ago
5 0

Answer:

<h3>P=6s</h3>

Step-by-step explanation:

<h3>to understand this</h3><h3>you need to know about:</h3>
  • linear function
<h3>tips and formulas:</h3>
  • a linear function is function with two variables one dependent another one is independent
<h3>let's solve:</h3>

since we can see what linear function is

the second condition is the best fit

<h3>The perimeter of a square, P, where the length of each side of the square is B represented by s</h3><h3>(P = 4s)</h3>

therefore

our answer is b

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What are the possible values of x in the equation | x + 5 | = 4?​
olga55 [171]

Answer:

x= -1

Step-by-step explanation:

x+5=4 or x+5= -4

x= -9 or x= -1

8 0
3 years ago
If the diameter of the circle is 24 cm, find its area correct to one decimal place.
Radda [10]

Answer:

A=pi times radius squared

24/2= 12 is the radius (since it's half of diameter)

A=pi times 12 squared

12 squared is 12 times 12 which is 144

A=pi times 144

A=452.389342

Rounded to 452.4

4 0
3 years ago
A rectangular school banner has a length of 36 inches and a width of 52 inches. A sign is made that is similar to the school ban
zalisa [80]

Answer:

<u>4212 : 1573</u> is the ratio.

Step-by-step explanation:

Given:

Length of rectangular school banner is 36 inches and width is 52 inches.

And, the sign made is similar to banner.

The sign's length is 22 inches.

Now, we have to find the ratio of the area of the banner to the area of the sign.

So, we have dimensions of rectangular school banner:

Length = 36 inches.

Width = 52 inches.

But, we have only length of sign:

Length = 22 inches.

Now, we have to find the width of sign by using cross multiplication method:

Let the width of sign be x.

<em>As, sign is similar to banner.</em>

So, if 36 inches is equivalent to 52 inches.

Then, 22 inches is equivalent to x.

\frac{36}{52} =\frac{22}{x}

<em>By cross multiplying we get:</em>

<em />36x=1144<em />

<em>Dividing both sides by 36 we get:</em>

x=31\frac{7}{9} .

<em>Hence, the width of sign is </em>31\frac{7}{9}<em> inches.</em>

Now, we find the area of banner and the area of sign by putting formula:

Area of banner = length × width.

Area\ of\ banner=36\times 52

Area\ of\ banner=1872\ square\ inches.

Now, area of sign:

Area\ of\ sign=length\times width\\\\Area\ of\ sign=22\times 31\frac{7}{9} \\\\Area\ of\ sign=22\times \frac{286}{9} \\\\Area\ of\ sign=\frac{6292}{9} \ square\ inches.

Now, to get the ratio of the area of the school banner to the area of the sign:

1872:\frac{6292}{9}

=\frac{1872}{\frac{6292}{9} } \\\\=\frac{16848}{6292}

<em>On simplifying we get:</em>

=\frac{4212}{1573}

=4212:1573.

Therefore, the ratio of the area of the school banner to the area of the sign is 4212:1573.

8 0
2 years ago
Need help with this!!!!
antoniya [11.8K]

Answer:

Cuatro es la respuesta también conocida como d

6 0
3 years ago
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A common tub is 54 inches long. What could be its length in centimeters? (1 inch = 2.54 cm)
ddd [48]

Answer:

137.16 cm

Step-by-step explanation:

its jus multiplication so 54in x 2.54cm

5 0
2 years ago
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