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2 years ago

Which scenario is best represented by a linear function?

Mathematics

1 answer:

nadezda [96]2 years ago

5 0

Answer:

Step-by-step explanation:

<h3>to understand this</h3><h3>you need to know about:</h3>

linear function

<h3>tips and formulas:</h3>

a linear function is function with two variables one dependent another one is independent

<h3>let's solve:</h3>

since we can see what linear function is

the second condition is the best fit

<h3>The perimeter of a square, P, where the length of each side of the square is B represented by s</h3><h3>(P = 4s)</h3>

therefore

our answer is b

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¿Cuál es el resultado de la siguiente operación? -4 +6 -5 +2<br> help

Gala2k [10]

Answer:

-1

Step-by-step explanation:

$(-4 +6)( -5 +2 )\\ - 4 + 6 = 2 \\ - 5 +2 = - 3 \\ 2 - 3 = - 1$

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1 year ago

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2 years ago

an outlier may be defined as a data point that is more than 1.5 times the interquartile range below the lower quartile or is mor

Ira Lisetskai [31]

Supposing a normal distribution, we find that:

The diameter of the smallest tree that is an outlier is of 16.36 inches.

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We suppose that tree diameters are normally distributed with <u>mean 8.8 inches and standard deviation 2.8 inches.</u>

<u />

In a normal distribution with mean $\mu$ and standard deviation $\sigma$ , the z-score of a measure X is given by:

$Z = \frac{X - \mu}{\sigma}$

The Z-score measures how many standard deviations the measure is from the mean.
After finding the z-score, we look at the z-score table and find the p-value associated with this z-score, which is the percentile of X.<u> </u>

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In this problem:

Mean of 8.8 inches, thus $\mu = 8.8$ .
Standard deviation of 2.8 inches, thus $\sigma = 2.8$ .

<u />

The interquartile range(IQR) is the difference between the 75th and the 25th percentile.

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25th percentile:

X when Z has a p-value of 0.25, so X when Z = -0.675.

$Z = \frac{X - \mu}{\sigma}$

$-0.675 = \frac{X - 8.8}{2.8}$

$X - 8.8 = -0.675(2.8)$

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75th percentile:

X when Z has a p-value of 0.75, so X when Z = 0.675.

$Z = \frac{X - \mu}{\sigma}$

$0.675 = \frac{X - 8.8}{2.8}$

$X - 8.8 = 0.675(2.8)$

$X = 10.69$

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$IQR = 10.69 - 6.91 = 3.78$

What is the diameter, in inches, of the smallest tree that is an outlier?

The diameter is <u>1.5IQR above the 75th percentile</u>, thus:

$10.69 + 1.5(3.78) = 16.36$

The diameter of the smallest tree that is an outlier is of 16.36 inches.

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A similar problem is given at brainly.com/question/15683591

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2 years ago

If f(x) = integral of 1/ (sqrt of t^3 +2)dt, then f'1 = ?

mihalych1998 [28]

Differentiating an integral removes the integral.

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I hope my answer has come to your help. Thank you for posting your question here in Brainly. We hope to answer more of your questions and inquiries soon. Have a nice day ahead!

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3 years ago

This equation will be in standard form if you subtract 2x2 from both sides and

prisoha [69]

Answer:

The answer is false

Step-by-step explanation:

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