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Arada [10]
2 years ago
8

the length of square A is the same as the perimeter of square B. The area of square A is 75 cm. Estimate the length of square B.

​
Mathematics
1 answer:
Elena-2011 [213]2 years ago
3 0

Answer:300cm

Step-by-step explanation:

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Hoochie [10]
P(bull's-eye) = 700/30000 x 100% = 2.33% ≈ 2%

option A is the correct answer.
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Write as a fraction 56:120
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56:120 = 56/120 = 7/15
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kramer
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den301095 [7]
1 .Fridays and Saturdays, she works 16 hours

16 x $9.70  = $155.20
answer: her gross pay in a week: $155.20

2.  7 hours on Wednesday, 6 hours on Thursday, and 9 hours on Friday. His gross pay for all three days was $196.90
7 + 6 + 9 = 22
196.90 / 22 = $8.95
answer: his hourly rate was $8.95

3.hourly rate of $11.28 per hour worked 46 hours last week. She works overtime for hours exceeding 40 hours in a week. She is paid overtime at a rate of time and a half. What was her gross pay last week?

$11.28 x 40 = $451.20 ---normal 40 hours paid

46 - 40 = 6 (6 hours over time)

11.28 + 11.28/ 2 = $16.92 (overtime pays a rate of time and a half)

6 * $16.92 = $101.52

$451.20(40hours) +  $101.52(6hours overtime) = $552.72

answer: her gross pay last week was $552.72

4. Paul received a $15 tip on a meal that cost $120. What percent of the meal cost was the tip?

15 / 120 = .125
.125 * 100 = 12.5%

answer: percent of the meal cost was the tip was 12.5%

5. Carly earns a weekly salary of $720 plus 4% commission. Last week, she sold $3250 worth of products. What was her gross pay?

4% = .04
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$720  + $ 130 = $850
answer:  her gross pay was $850

5 0
3 years ago
Read 2 more answers
A survey found that​ women's heights are normally distributed with mean 63.3 in. and standard deviation 2.7 in. The survey also
mylen [45]

Answer:

A) There is a 100% chance of meeting the height requirement for women.

B) There is a 99.89% chance of meeting the height requirement for men.

C) New height requirements are:

71.9 inches for men and 58.9 inches minimum for women.

At least 58.9 inches and at most 71.9 inches.

Step-by-step explanation:

This question involves finding z values which tell us the percentage from 0 to x.

z = (x-μ)/σ

A) In this question, the minimum sample point is 4 ft 9 inches or converting to inches, we have;(4*12) + 9 =57 inches.

The maximum sample point is 6 ft 4 inches which in inches gives; (6*12) + 4 = 76 inches

For the minimum point;

z = (57 - 63.3)/2.7 = -2.33

From the z-distribution table, this equates to 0.0099.

The maximum;

z = (76 - 63.3)/2.7 = 4.70

From the z-table, it gives 0.999.. Basically 100%.

So there is a 100% chance of meeting the height requirement for women.

B) For men;

the minimum z = (57 - 67.3)/2.8 = -3.68 which gives 0.00012 from the z-distribution table.

The maximum;

z = (76 - 67.3)/2.8 = 3.07 which gives 0.9989 from the z-distribution table. Basically, 99.89%.

So there is a 99.89% chance of meeting the height requirement for men.

C) To exclude the tallest 5% of men, we need to find the z-value for 0.95 and then solve for x.

Thus from the z-table, z = 1.65. So;

1.645 = (x - 67.3)/2.8

4.606 = x - 67.3

x = 67.3 + 4.606

x ≈ 71.9 inches for men.

So, Current minimum is okay.

To exclude the shortest 5% of women, we need to find the z for 0.05.

From the z-distribution table, it has a value of -1.645. So;

-1.645 = (x - 63.3)/2.7

-4.4415 = x - 63.3

x = 63.3 - 4.4415

x ≈ 58.9 inches minimum.

So, Current maximum is okay.

5 0
3 years ago
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