Answer:
(1, 3 )
Step-by-step explanation:
Given the 2 equations
2x + y = 5 → (1)
- x + y = 2 → (2)
Rearrange (1) expressing y in terms of x by subtracting 2x fro both sides
y = 5 - 2x → (3)
Substitute y = 5 - 2x into (2)
- x + 5 - 2x = 2
- 3x + 5 = 2 ( subtract 5 from both sides )
- 3x = - 3 ( divide both sides by - 3 )
x = 1
Substitute x = 1 into (3) for corresponding value of y
y = 5 - 2(1) = 5 - 2 = 3
solution is (1, 3 )
Answer:
[1,∞) Third one down.
Step-by-step explanation:
Comment
A couple of notes so you know what we are looking for.
- (a,b) means that neither a nor b are included in the interval.
- [a,b] means that both a and b are included in the interval/
- Range means the y value.
Graph
The graph shows that the interval of the range is from 1 to infinity. Infinity is never part of a domain or a range. The bracket after infinity must be ( or ) depending on where infinity is. Nothing is eliminated by that fact.
The low point is 1, not minus 1. So the first and second choice are both incorrect.
The graph never crosses the x axis. - infinity cannot be even a limit of the interval. That makes the second and the last one incorrect.
Only the third one down is left. [1, ∞) is left. It is correct. 1 is part of the interval. Infinity is not.
7 feeties
Step-by-step explanation:
ok ok ok okkkkkkkkkkkkkkkk
Answer:
I think it's a
Step-by-step explanation:
because obviously the pyramid has a square base and triangles around it, which rules out c, and if you try and fold them together in your head
Let <em>X</em> be a random number selected from the interval. Then the probability density for the random variable <em>X</em> is

8 and 10 are the only even integers that fit the given criterion (6 is more than 0.25 away from 6.35), so that we're looking to compute
P(|<em>X</em> - 8| < 0.25) + P(|<em>X</em> - 10| < 0.25)
… = P(7.75 < <em>X</em> < 8.25) + P(9.75 < <em>X</em> < 10.25)
… = P(7.75 < <em>X</em> < 8.25) + P(9.75 < <em>X</em> < 10)
(since P(<em>X</em> > 10) = 0)
… = 0.2740 (8.25 - 7.75) + 0.2740 (10 - 9.75)
… = 0.2055