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3 years ago

What is an equation of the line that passes through the points (-2,5) and

Mathematics

1 answer:

VLD [36.1K]3 years ago

8 0

y=-3x-1

Is your answer if thats how you need it.

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16 - 2r = -3r + 6r +1

Alona [7]

Answer:

r=3

Step-by-step explanation:

Simplify the expression

16-2r=3r+1

isolate r by adding 2r to both sides

16=5r+1

isolate the numbers by subtracting 1 from both sides

15=5r

divide both sides by 5 to completely isolate r

r=3

8 0

3 years ago

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write an equation in slope intercept form with a positive slope less than one and a y intercept between -10 and 10

Pachacha [2.7K]

Write an equation in slope intercept form with a positive slope less than one and a y intercept between -10 and 10

5 0

4 years ago

Trig with a picture included

MakcuM [25]

Answer:

26,167 m

Step-by-step explanation:

Step 1: Find the other angle of the complementary set

90 - 17 = 73°

Step 2: Find the angle of elevation from the ship

180 - (73 + 90) = 17°

Step 3: Use tan∅ to find distance

tan17° = 8000/x

xtan17° = 8000

x = 8000/tan17°

x = 26166.8

5 0

4 years ago

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The distance of a golf ball from the hole can be represented by the right side of a parabola with vertex (−1, 8). The ball reach

sukhopar [10]

Answer:

The required equation is:

$y = -\frac{4}{3}t^2 -\frac{8}{3}t + 4$

Explanation:

Let us assume that the hole is at y = 0m, with x as the time.

From the question we have (-1s, 8m) as the vertex (here x being the time variable is supposed to be in seconds and y being the distance variable is supposed to be in meters)

At x = 1s, the ball gets to the hole, therefore we have point (1s, 0m)

We know that the vertex of the parabola y = ax² + bx + c is at

$x =\frac{-b}{2a}$

therefore we have:

$-1 = \frac{-b}{2a}$

We then have the following equations:

$8 = a\times -1^2 + b\times -1 + c$

$0 = a\times -1^2 + b\times 1 + c$

$-1 = \frac{-b}{2a}$

From the 3rd equation we have

1 X 2a = b.

Therefore we have:

$8 = a\times -1^2 - 1\times 2a\times1 + c$

$0 = a\times 1^2 + 1 \times2a\times 1 + c$

We can simplify both equations and get:

$8 = a\times( -1^2 - 2s^2) + c = -a\times 3^2 + c$

$0 = a\times(1^2 + 2^2) + c = a\times 3^2 + c$

The first equation now becomes:

$8 = -a\times 3 - a\times 3 = -a\times 6$

$a = frac{8}{-6} = -\frac{4}{3}$

With a, we can find the values of c and b.

$c = -a\times3 = -(-\frac{4}{3})*3 = 4$

$b = 1\times 2a = 1\times 2(-\frac{4}{3})= -\frac{8}{3}$

Then the equation is:

$y = -\frac{4}{3}t^2 -\frac{8}{3}t + 4$

6 0

3 years ago

It’s drag and drop please help

Serhud [2]

The first one is 4n+7=15, the second one is 1/4(n-15), the third one is 1/4n-15, the fourth one is n/7=4, and the last one is n4+7=15

7 0

3 years ago

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