So I guess we are solving for x here :)
So here is my work...
a=2x+6xz
Basically I think it would be
a=6xz+2x

WAIT WAIT NO I'M WRONG FORGIVE ME!

It's x=a/2(1+3z)

5 0

2 years ago

Read 2 more answers

Compare and Contrast how you would factor x^2−9 and x^2+9. For full credit, make sure you explain why they are factored differen

marishachu [46]

The factored form of the expression $x^2 - 9$ is $(x+3)(x-3)$

The expression x^2 + 9 has no real roots hence cannot be factored

Quadratic equations are equations with a degree of 2.

Given the quadratic function $x^2-9 \ and \ x^2+9$

For the function $x^2 - 9$

$=x^2-9\\=x^2-3^2$

Using the difference of two squares:

$a^2-b^2=(a-b)(a+b)\\x^2-3^2=(x-3)(x+3)$

For the expression x^2 + 9

The expression x^2 + 9 has no real roots hence cannot be factored

Learn more on factorization here: brainly.com/question/20293447

7 0

2 years ago

Need some help please

zaharov [31]

Answer:

Step-by-step explanation:

number 2

6 0

2 years ago