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mrs_skeptik [129]
3 years ago
7

If 6x +3= 2x+ 19, then x =

Mathematics
2 answers:
stepladder [879]3 years ago
6 0

Answer:

x = 4

Step-by-step explanation:

6x + 3 = 2x + 19  ------ subtract 3 both sides

6x + 3 - 3 = 2x + 19 - 3   simplify

6x = 2x + 16         ------ subtract 2x both sides

6x - 2x = 2x + 16 - 2x      simplify

4x = 16

x = 16 / 4

x = 4

Vsevolod [243]3 years ago
3 0

Answer: x = 4

Step-by-step explanation: If the variable appears on both sides of the equation, we put the variables together on one side of the equation and the numbers together on the other side of the equation.

So let's put our variables on the left side by first subtracting

2x from both sides of the equation to get 4x + 3 = 19.

Next, we subtract 3 from both sides to get 4x = 16.

Finally, we divide both sides by 4 to get x = 4.

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What is the domain and range of the relation shown in
Leya [2.2K]

Answer:

Domain : {10, 15, 19, 32}

Range: {-1, 5, 9}

Step-by-step explanation:

As the table of the relation is given as follows:

<em>X                Y</em>

<em>10               5</em>

<em>15               9</em>

<em>19               -1</em>

<em>32             5  </em>

From this table, we can define the relation by combining the ordered pairs from the table. Each and every order pair consists of x-coordinate and corresponding y-coordinate of any corresponding point.

So, the relation from the table can be made as follows:

                            relation : {(10, 5), (15, 9), (19, -1), (32, 5)}

Domain of a relation consists of all the x-coordinates (first elements) of order pairs.

Range of a relation consists of all the y-coordinates (second elements) of ordered pairs.

So, domain  and range of relation will be as follows:

                                  Domain : {10, 15, 19, 32}

                                  Range: {-1, 5, 9}

<em>Note: If there is any </em><em>duplicate</em><em> element in any x or y-coordinate of any ordered pair, it will be written only </em><em>once </em><em>when we determine domain and range. Here, in this example, 5 is duplicate, so, it will be mentioned only one time when we determine the range of this relation.</em>

Keywords:  domain, relation, range

Learn more about domain and range of a relation from brainly.com/question/11422136

#learnwithBrainly

6 0
3 years ago
Who can help to develop and solve an algebraic equation for this question? ​
mixer [17]

Answer:

25 mins

Step-by-step explanation:

Harpeet worked -- x mins

Aiysha worked -- 2x mins

If Aiysha worked 50 mins, Harpeet worked:

2x = 50

x = 25 mins

Thenks and mark me brainliest :))

3 0
3 years ago
Midsegment of triangle <br> Find the distance across the lake
Marizza181 [45]

Answer:

The distance across the lake is 3.5 km

Step-by-step explanation:

Hypotenuse is divided in equal parts. Thus both sides are divided in the same proportion.

6 0
3 years ago
Read 2 more answers
Find the hypotenuse of a right triangle that has one side of 7 cm and another<br> one of 3 cm.
Over [174]
The hypotenuse is the square root of 58.
a^2+b^2=c^2
7^2+3^2=c^2
49+9=c^2
58=c^2
c= square root of 58
5 0
3 years ago
Read 2 more answers
Which could you use to prove triangle AED is congruent to triangle CEB?
Hunter-Best [27]

Answer:

Option (C)

Step-by-step explanation:

Given:

In right triangles ΔAED and CEB,

m∠AED = m∠CEB = 90°

DE ≅ BE

AD ≅ BC

To prove:

ΔAED ≅ ΔCEB

                    Statements                         Reasons

1). m∠AED = m∠BC = 90°              1). Given

2). DE = BE                                     2). Given

3). AD = BC                                    3). Given

4). ΔAED ≅ ΔCEB                          4). By HL theorem of congruence

Option (C) is the answer.

4 0
3 years ago
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