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Tamiku [17]
4 years ago
12

laura decides to walk to her job. she walks 1 1\2 miles in 3\5 hour. what is laura's walking rate? laura's job is 4 1\2 miles aw

ay. if she starts walking to her job at 9:00 a.m. and is scheduled to start work at 11:00 a.am., will she arrive at her job on time?
Mathematics
1 answer:
Nuetrik [128]4 years ago
4 0
To find the rate in miles per hour, divide the miles by the hours.

(1 1/2 miles)/(3/5 hour) =

= 3/2 miles * (5/3 hour)

= 5/2 mph

= 2 1/2 mph

Her walking rate is 2 1/2 mph.

(4 1/2 miles) / ( 2 1/2 mph) =

= 9/2 miles / (5/2 mph)

= 9/2 * 2/5 hours

= 9/5 hours

= 1 4/5 hours

From 9:00 a.m. to 11 a.m., she has 2 hours, but she only needs 1 4/5 hours to walk, so she will make it to work on time.
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6sqrt2(cos(-5pie/4)+isin(-5pie/5))

Step-by-step explanation:

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the total length of 4 blue banners an 5 yellow banners is 49 meters. the total length of 2 blue banners an 1 yellow banner is 17
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An X-ray machine for animals costs$125,000. If the loan is for 10 years, an the interest paid is $65,625, what is the interest r
Rina8888 [55]
The answer is 5.25%.

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3 0
3 years ago
The expected number of typographical errors on a page of a certain magazine is .2. What is the probability that an article of 10
Pavel [41]

Answer:

a) The probability that an article of 10 pages contains 0 typographical errors is 0.8187.

b) The probability that an article of 10 pages contains 2 or more typographical errors is 0.0175.

Step-by-step explanation:

Given : The expected number of typographical errors on a page of a certain magazine is 0.2.

To find : What is the probability that an article of 10 pages contains

(a) 0 and (b) 2 or more typographical errors?

Solution :

Applying Poisson distribution,

N\sim Pois(0.2)

P(N=r)=\frac{e^{-np}(np)^r}{r!}

where, n is the number of words in a page

and p is the probability of every word with typographical errors.

Here, n=10 and E(N)=np=0.2

a) The probability that an article of 10 pages contains 0 typographical errors.

Substitute r=0 in formula,

P(N=0)=\frac{e^{-0.2}(0.2)^0}{0!}

P(N=0)=\frac{e^{-0.2}}{1}

P(N=0)=e^{-0.2}

P(N=0)=0.8187

The probability that an article of 10 pages contains 0 typographical errors is 0.8187.

b) The probability that an article of 10 pages contains 2 or more typographical errors.

Substitute r\geq 2 in formula,

P(N\geq 2)=1-P(N

P(N\geq 2)=1-[P(N=0)+P(N=1)]

P(N\geq 2)=1-[\frac{e^{-0.2}(0.2)^0}{0!}+\frac{e^{-0.2}(0.2)^1}{1!}]

P(N\geq 2)=1-[e^{-0.2}+e^{-0.2}(0.2)]

P(N\geq 2)=1-[0.8187+0.1637]

P(N\geq 2)=1-0.9825

P(N\geq 2)=0.0175

The probability that an article of 10 pages contains 2 or more typographical errors is 0.0175.

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Use geometric shapes to create a logo that will fit in a measuring 15 cm by 15 cm
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A geometric shapes that can be used to create a logo that will fit in a measuring 15 cm by 15 cm is to use a square.

<h3>What are geometric shapes?</h3>

It should be noted that geometric shapes are the figure of area that is closed by a boundary.

In this case, a geometric shapes that. an be used to create a logo that will fit in a measuring 15 cm by 15 cm is to use a square.

This is because all the sides in a square are equal.

Learn more about shapes on:

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