Answer:
Jogging 6th time.
Step-by-step explanation:
We have been given that Vicki started jogging the first time she ran she ran 3/16 mile the second time she ran 3/8 mile and the third time she ran 9/16 mile.
We can see that the distance Vicki covers each time forms a arithmetic sequence, where 1st term is 3/16.
We know that an arithmetic sequence is in form
, where,
= nth term of sequence,
= 1st term of sequence,
n = Number of terms in sequence,
d = Common difference.
Let us find common difference of our given sequence as:

Since Vicki needs to cover more than 1 mile, so we nth term of sequence should be greater than 1.

Let us solve for n.





We can also write next terms of our sequence as:

Therefore, Vicki will run more than 1 mile when she is jogging for 6th time.
Answer:
I am pretty sure it is the second option
Step-by-step explanation:
Hope this helps
The answer for this would be negative eight
Answer:
4times1/4(y-(-25/4))=(x-(-3/2)) small 2
4p(y-k)=(x-h)small 2
something like that I belive
or just y>xsmall2+3x-4
If you're looking for x then it's 7. The value of -4 is -4.