Can I get this answer needed ASAP!! S= 18w + 38

a construction crew built 4 1/2 miles of Road and 3 3/8 days. What is the unit rate in miles per day? Write your answer as a fra

sineoko [7]

The construction crew took $3\frac{3}{8}$ days to build $4\frac{1}{2}$ miles of road.

Therefore, in 1 day, the crew built $\frac{4\frac{1}{2} }{3\frac{3}{8} }$ miles of road

= $\frac{\frac{9}{2} }{\frac{27}{8} } =\frac{9}{2}times\frac{8}{27}=\frac{4}{3}$ miles of road

Thus, the required rate is $\frac{4}{3}$ miles or $1\frac{1}{3}$ miles per day.

5 0

4 years ago

Martin finds a shirt on sale for 20% off at a department store. The original price was $20. Martin must also pay a 7.5% sales ta

mars1129 [50]

Answer: You will pay $13.52 for this shirt.

Step-by-step explanation: 0.9435

Since the tax is 7.5%, you have to multiply 12.58 by 7.5% to find the amount of money paid as tax.

7.5% = 0.075

12.58 x 0.075 = 0.9435

Since we are dealing with money we have to round to the nearest hundredth -- 0.9435 = 0.94

Then to find the final cost of the shirt, we have to add 12.58 and 0.94 to get $13.52.

3 0

3 years ago

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A ball is thrown into the air from a height of 4 feet at time t = 0. The function that models this situation is h(t) = -16t2 + 6

katrin2010 [14]

Answer:

Part a) The height of the ball after 3 seconds is $49\ ft$

Part b) The maximum height is 66 ft

Part c) The ball hit the ground for t=4 sec

Part d) The domain of the function that makes sense is the interval

[0,4]

Step-by-step explanation:

we have

$h(t)=-16t^{2} +63t+4$

Part a) What is the height of the ball after 3 seconds?

For t=3 sec

Substitute in the function and solve for h

$h(3)=-16(3)^{2} +63(3)+4=49\ ft$

Part b) What is the maximum height of the ball? Round to the nearest foot.

we know that

The maximum height of the ball is the vertex of the quadratic equation

so

Convert the function into a vertex form

$h(t)=-16t^{2} +63t+4$

Group terms that contain the same variable, and move the constant to the opposite side of the equation

$h(t)-4=-16t^{2} +63t$

Factor the leading coefficient

$h(t)-4=-16(t^{2} -(63/16)t)$

Complete the square. Remember to balance the equation by adding the same constants to each side

$h(t)-4-16(63/32)^{2}=-16(t^{2} -(63/16)t+(63/32)^{2})$

$h(t)-(67,600/1,024)=-16(t^{2} -(63/16)t+(63/32)^{2})$

Rewrite as perfect squares

$h(t)-(67,600/1,024)=-16(t-(63/32))^{2}$

$h(t)=-16(t-(63/32))^{2}+(67,600/1,024)$

the vertex is the point (1.97,66.02)

therefore

The maximum height is 66 ft

Part c) When will the ball hit the ground?

we know that

The ball hit the ground when h(t)=0 (the x-intercepts of the function)

so

$h(t)=-16t^{2} +63t+4$

For h(t)=0

$0=-16t^{2} +63t+4$

using a graphing tool

The solution is t=4 sec

see the attached figure

Part d) What domain makes sense for the function?

The domain of the function that makes sense is the interval

[0,4]

All real numbers greater than or equal to 0 seconds and less than or equal to 4 seconds

Remember that the time can not be a negative number

6 0

3 years ago

What is the value of (-12) + (- 33)? Can someone explain the steps to the answer please?.. ASAP

mina [271]

Answer:

(-12) + (-33) = (-45)

5 0

3 years ago

Find the measure of 26.<br> 4 6 = [?]<br> 249<br> 46

Basile [38]

ANSWER:

We know that the sum of angles of same sides in parallel lines are supplementary(180°).

So, ∠6 + 24° = 180°

∠6 = 180° - 24°
∠6 = 156°.

7 0

3 years ago

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