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Sladkaya [172]
3 years ago
6

Evaluate 9/m + 4 when m = 3

Mathematics
2 answers:
s344n2d4d5 [400]3 years ago
8 0

Answer:

7

Step-by-step explanation:

First, plug in m.

9/3+4

Because this equation has multiple operations, we need to use the order of operations, aka PEMDAS. It stands for Parentheses, Exponents, Multiplication/Division, and Addition/Subtraction. First in the order of operations that we have in this equation is multiplication/division. So, we need to divide 9/3 before adding.

9/3=3

The equation is now simplified to 3+4, which is 7.

Hope this helps! Have a great day :D

Maurinko [17]3 years ago
6 0

Answer:

Step-by-step explanation:

9/3 = 3

3+4 = 7

The answer is 7!

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When steve woke up. his temerature was 102. two hours later it was 3 lower what is his temerature now?
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Steve's original temperature - 102

2 hours later it dropped 3 degrees

102 - 3 = 99

Steve's current temperature is 99.
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What is this -5/7 divide by -1/3
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Answer:

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Step-by-step explanation:

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A manufacturer uses production method to produce steel rods. A random sample of 17 steel rods resulted in lengths with a standar
Arisa [49]

Answer:

\chi^2 =\frac{17-1}{12.15} 22.09 =15.87

Traditional method

We can find a critical value in the chi square distribution with df =16 who accumulates \alpha/2 =0.05 of the area on each tail and we got:

\chi^2_{crit}= 7.962

\chi^2_{crit}=26.296

Since the calculated value is between the two critical values we don't have enough evidence to conclude that the true deviation is NOT significantly different from 3.5 cm

Confidence level method

We can find the p value like this

p_v =2*P(\chi^2 >15.87)=0.92

Since the p value is higher then the significance level we have enough evidence to FAIL to reject the null hypothesis and we can conclude that the true deviation is NOT significantly different from 3.5 cm

Step-by-step explanation:

Data provided

n=17 represent the sample selected

\alpha=0.1 represent the significance

s^2 =4.7^2 =22.09 represent the sample variance

\sigma^2_0 =3.5^2 =12.15 represent the value to check

Null and alternative hypothesis

We want to verify if the new production method has lengths with a standard deviation different from 3.5 cm, so the system of hypothesis would be:

Null Hypothesis: \sigma^2 = 12.15

Alternative hypothesis: \sigma^2 \neq 12.15

The statistic for this case is given by:

\chi^2 =\frac{n-1}{\sigma^2_0} s^2

The degrees of freedom are:

df =n-1= 17-1=16

\chi^2 =\frac{17-1}{12.15} 22.09 =15.87

Traditional method

We can find a critical value in the chi square distribution with df =16 who accumulates \alpha/2 =0.05 of the area on each tail and we got:

\chi^2_{crit}= 7.962

\chi^2_{crit}=26.296

Since the calculated value is between the two critical values we don't have enough evidence to conclude that the true deviation is significantly different from 3.5 cm

Confidence level method

We can find the p value like this

p_v =2*P(\chi^2 >15.87)=0.92

Since the p value is higher then the significance level we have enough evidence to FAIL to reject the null hypothesis and we can conclude that the true deviation is significantly different from 3.5 cm

7 0
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will support for 110 days
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