Answer:
![\sqrt[5]{x - 9}](https://tex.z-dn.net/?f=%5Csqrt%5B5%5D%7Bx%20-%209%7D%20)
Step-by-step explanation:
y=x^5+9
To find inverse function make x the subject, first:
y=x^5+9
y - 9 = x^5
x = ![\sqrt[5]{y - 9}](https://tex.z-dn.net/?f=%5Csqrt%5B5%5D%7By%20-%209%7D%20)
![y^{-1} = \sqrt[5]{x - 9}](https://tex.z-dn.net/?f=y%5E%7B-1%7D%20%20%3D%20%5Csqrt%5B5%5D%7Bx%20-%209%7D%20)
so inverse function of y=x^5+9 is
Answer:
Step-by-step explanation:
Our equation is:
First we dritribute
Now we have, 
light terms
and we get
Answer:
1 / 4 ( or ) 0.25
Step-by-step explanation:
Let the missing number be " x ".
12 . x = 3
x = 3 / 12
x = 1 / 4
( or )
x = 0.25
The local minimum of function is an argument x for which the first derivative of function g(x) is equal to zero, so:
g'(x)=0
g'(x)=(x^4-5x^2+4)'=4x^3-10x=0
x(4x^2-10)=0
x=0 or 4x^2-10=0
4x^2-10=0 /4
x^2-10/4=0
x^2-5/2=0
[x-sqrt(5/2)][x+sqrt(5/2)]=0
Now we have to check wchich argument gives the minimum value from x=0, x=sqrt(5/2) and x=-sqrt(5/2).
g(0)=4
g(sqrt(5/2))=25/4-5*5/2+4=4-25/4=-9/4
g(-sqrt(5/2))=-9/4
The answer is sqrt(5/2) and -sqrt(5/2).
first you put 12 over 100 and that is 12/100 and then simplify
