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3 years ago

11

The photo is 2.5 inches by 3.5 inches. You decide to dilate the photo to 5 inches by 7 inches at the store. What is the scale fa

ctor of this dilation?

2 answers:

gizmo_the_mogwai [7]3 years ago

8 0

Answer:

2

Step-by-step explanation:

melamori03 [73]3 years ago

7 0

2. You’d do 5 divided by 2.5 which = 2

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Please answer at least one of them

Ray Of Light [21]

The equation of a circle with radius r and center at point (a, b) is given by
(x - a)^2 + (y - b)^2 = r^2
1.) For the circle given by x^2 + y^2 = 24
(x - 0)^2 + (y - 0)^2 = (√24)^2
Therefore, center = (0, 0) and radius = √24 = 4.9 units

3.) x^2 + y^2 -10x -2y = -10
x^2 - 10x + (-5)^2 + y^2 - 2y + (-1)^2 = -10 + (-5)^2 + (-1)^2
x^2 - 10x + 25 + y^2 - 2y + 1 = -10 + 25 + 1
(x - 5)^2 + (y - 1)^2 = 16
(x - 5)^2 + (y - 1)^2 = 4^2

6 0

3 years ago

What’s is the answer

77julia77 [94]

C and E, I believe since the other theorems don’t exist and AAS does not apply

5 0

3 years ago

A sequence is defined by the following: an = 4n – 1 What is a1?

Semmy [17]

So it is saying to find a1. That means n = 1.

a1 = 4 (1) - 1

a1 = 4 - 1

a1 = 3

7 0

3 years ago

Read 2 more answers

Out of 300 people sampled, 237 preferred Candidate A. Based on this, estimate what proportion of the voting population ( π ) pre

Ronch [10]

Answer:

And the 95% confidence interval would be given (0.744;0.836).

$0.744 \leq \pi \leq 0.836$

Step-by-step explanation:

1) Data given and notation

n=300 represent the random sample taken

X=237 represent the people who prefers the Candidate A

$\hat p=\frac{237}{300}=0.79$ estimated proportion of people who prefers the Candidate A

$\alpha=0.05$ represent the significance level (no given, but is assumed)

Confidence =95% or 0.95

p= population proportion of people who prefers the Candidate A

A confidence interval is "a range of values that’s likely to include a population value with a certain degree of confidence. It is often expressed a % whereby a population means lies between an upper and lower interval".

The margin of error is the range of values below and above the sample statistic in a confidence interval.

Normal distribution, is a "probability distribution that is symmetric about the mean, showing that data near the mean are more frequent in occurrence than data far from the mean".

2) Calculating the interval for the proportion

The confidence interval would be given by this formula

$\hat p \pm z_{\alpha/2} \sqrt{\frac{\hat p(1-\hat p)}{n}}$

For the 95% confidence interval the value of $\alpha=1-0.95=0.05$ and $\alpha/2=0.025$ , with that value we can find the quantile required for the interval in the normal standard distribution.

$z_{\alpha/2}=1.96$

And replacing into the confidence interval formula we got:

$0.79 - 1.96 \sqrt{\frac{0.79(1-0.79)}{300}}=0.744$

$0.79 + 1.96 \sqrt{\frac{0.79(1-0.79)}{300}}=0.836$

And the 95% confidence interval would be given (0.744;0.836).

We are confident that about 74.4% to 83.6% of people prefers Candidate A

5 0

3 years ago

Is 14.1 a rational number

Hatshy [7]

Yes, it is a rational number

5 0

3 years ago