Answer:
657483920
Step-by-step explanation:
this is incorrect
Answer:
Dfrew
Step-by-step explanation:
Answer:
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<u>Answer:</u>
Standard form of a line passing through (-2, 4) and having slope of -1/7 is x + 7y = 26
<u>Solution:</u>
Given that we need to determine standard form of a line that goes through (-2 , 4) and slope of the line is -1/7
Standard form of line passing through point ( a , b ) and having slope m is given by
(y – b) = m ( x – a) --------(1)
In our case given point is ( -2 , 4 ) and slope is -1/7 that means
a = -2 , b = 4 , m = -(1/7)
On substituting given value of a , b and m is equation (1) we get


=> 7( y - 4 ) = -x – 2
=> 7y + x = -2 + 28
=> x + 7y = 26
Hence standard form of a line passing through (-2,4) and having slope of –(1/7) is x + 7y = 26
Answer:
let remaining angle in heptagon be a.
a+64=180(linear pair)
a=116
again
x+155+90+163+a+121°=720(sum of interior angle of hexagon is (6-2)×180°)
x+529+a=720
x+116=720-529
x=191-116=75