Answer:
Area will be 397.54
Step-by-step explanation:
See attachment.....
The area that the dog can wander based on the information provided will be 931π.
<h3>How to calculate the area?</h3>
From the information, we are told that the dog dog is attached to a 35-foot rope fastened to the outside corner of a fenced-in garden that measures 28 feet by 36 feet.
In this case, the dog is in an outside corner. The dog can trace 3/4 of a circle when it starts walking in a circle away form the wall.
The area that the dog can wander will be:
= 3/4(π35²) + 1/4(π(35 - 28)²)
= 3/4π(35)² + 1/4π(7)²
= (3/4 × 1225)π + (1/4 × 49)π
= 918.75π + 12.25π
= 931π
Therefore, the area that the dog can wander based on the information provided will be 931π.
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Please, write "x^3" for "the cube of x," not "x3." "^" denotes exponentiation.
Then you have g(x) = x^3 - 5 and (I assume) h(x) = 2x - 2.
1) evaluate g(x) at x = -2: g(-2) = (-2)^3 - 5 = -8 - 5 = -13
2) let the input to h(x) be -13: h(-13) = 2(-13) - 2 = -28 (answer)
Answer:
8 i think im not really sure
Step-by-step explanation:
If your looking for the equation it would be 3.95 + 0.85t = Price
