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torisob [31]
3 years ago
14

Please help

Mathematics
2 answers:
MAXImum [283]3 years ago
7 0

Answer:

0.3243

Step-by-step explanation:

son4ous [18]3 years ago
4 0

Answer:

Step-by-step explanation:

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Write functions for each of the following transformations using function notation. Choose a different letter to represent each f
joja [24]

Answer:

1. Translation: g(x) = f(x-a)+b.

2. Reflection around y-axis: h(x) = f(-x)

3. Reflection around x-axis: k(x) = -f(x)

4. Rotation of 90° : R_{90} (x,y)=(-y,x)

5. Rotation of 180° : R_{180} (x,y)=(-x,-y).

6. Rotation of 270° : R_{180} (x,y)=(y,-x).

Step-by-step explanation:

Let us assume that the transformations namely translation, reflection are applied to a function f(x) and the rotation is applied to the point ( x,y ).

So, according to the options:

We know that 'translation moves the image in horizontal and vertical direction'.

1. As we have to translate the function f(x) 'a' units to the right and 'b' units up. So, the new form of the function becomes g(x) = f(x-a)+b.

Further, we know that 'reflection means to flip the image around a line'.

2. As, we have to reflect the function f(x) around y-axis. The new form of the function is h(x) = f(-x).

3. As, we have to reflect the function f(x) around x-axis. The new form of the function is k(x) = -f(x).

Since, 'rotation turns the image around a point to a certain degree'.

4. As, we have to rotate ( x,y ) counter-clockwise to 90° about the origin, the new form of the function is R_{90} (x,y)=(-y,x).

5. As, we have to rotate ( x,y ) counter-clockwise to 180° about the origin, the new form of the function is R_{180} (x,y)=(-x,-y).

6. As, we have to rotate ( x,y ) counter-clockwise to 270° about the origin, the new form of the function is R_{180} (x,y)=(y,-x).

5 0
3 years ago
SOMEONE HELP ME HURRY ASAP PLEASE ILL CASHAPP PLEASE HELP
Colt1911 [192]

Answer:

48 il take brainliest instead lol

Step-by-step explanation:

6 0
3 years ago
Read 2 more answers
Is the following relation a function? *
spayn [35]

Answer:

No.

Step-by-step explanation:

Well at first glance it might seem so but there are two points particularly that can tell you that these points cannot be within a function.

The points (3,2) and (3,-2) will yield an undefined slope (a straight vertical line). There is no possibility that the other points can be in this line (as their y - values are different) and there is no possibilty that this is a function at all according to the vertical line test (the test is that if you draw a vertical line that there shouldn't be more than one point on it).

8 0
3 years ago
I need help in the two questions
Sholpan [36]
Y-5=3-9 (y+2)
Solve for y
Distribute the 9 to (y+2)
Y-5=3-9y-18
Y-5=-15-9y
+9y to both sides
10y-5=-15
+5 to both sides
10y=-10
÷10 both sides
Y= -1

2 (x-7)-10=12-4x
Solve for X
Distribute 2 to (x-7)
2x-14-10=12-4x
2x-24=12-4x
+4x to both sides
6x-24=12
+24 to both sides
6x=36
÷6 to both sides
X=6
3 0
3 years ago
What are the zeros of the function f(x)=x^2-2x-15?
valkas [14]
To find the zeros of this function, we must first set the entire function equal to 0

f(x) = x² - 2x - 15 = 0

Since this is a quadratic function, we must use the quadratic formula, which is:

\frac{-b +/-  \sqrt{b^{2} - 4(a)(c) } }{2a}

Let's assign a, b, and c using our first function
x² means a = 1 (because it could be written as 1x²)
-2x means b = -2
-15 means c = -15

Now let's plug those in:

\frac{-(-2) +/- \sqrt{(-2)^{2} - 4(1)(-15) } }{2(1)}

which simplifies to:

\frac{2 +/- \sqrt{(4 + 60} }{2}

Simplified further:

\frac{2 +/- \sqrt{(64} }{2}
\frac{2 +/- 8 }{2}
And divide it by the 2 on the bottom gives us:

2 +/- 4

2+4 = 6
2-4 = -2

So the zeros of this function are -2 and 6
6 0
3 years ago
Read 2 more answers
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