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3 years ago

8

The average fish at a fishing tournament was 12.4 pounds. Some of the weight last of the fish are shown on the table:

1 answer:

Ivanshal [37]3 years ago

6 0

Answer:

15.5kg

Step-by-step explanation:

12.4kg × 5 = 62kg,

= 62kg - (14.6kg + 11.4kg + 10.3kg + 10.2kg)

= 62kg - 46.5kg

= 15.5kg

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inn [45]

There is no solution to this system of equations because they both have the same slope.

If two lines have the same slope, but are not identically the same line, then they will never intersect. There is no pair (x, y) that could satisfy both equations, because there is no point (x, y) that is simultaneously on both lines. Therefore, these equations are said to be inconsistent, and there is no solution.

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3 years ago

Jason volunteered at the pet shelter twice as many times as keith. Noah volunteered three times more often than jason. Keith vol

Alchen [17]

Answer:

$y = 6\cdot z$

$y$ - Number of times that Noah volunteered at pet shelter.

$z$ - Number of times that Keith volunteered at pet shelter.

Step-by-step explanation:

After reading the statement of the problem, the following variables are described below:

$x$ - Number of times that Jason volunteered at pet shelter.

$y$ - Number of times that Noah volunteered at pet shelter.

$z$ - Number of times that Keith volunteered at pet shelter.

The following two relations are presented herein:

Noah and Jason

$y = 3\cdot x$

Jason and Keith

$x = 2\cdot z$

The relationship between the number of times Noah and Keith volunteered is:

$y = 6\cdot z$

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3 years ago

PLEASE HELP ME ASAP ILL MARK BRIANLIEST!!!!!!!!! ANSWER THE QUESTIONS AND DO THE STEPS TOO PLEASEE

Anon25 [30]

Answer:

1). t ≥ - $\frac{3}{2}$

2). k ≥ $\frac{16}{3}$

3). y < - $\frac{1}{2}$

4). b > $\frac{250}{9}$

5). w ≤ 0

Step-by-step explanation:

1). $14(\frac{1}{2}-t)\leq 28$

$\frac{14}{14}(\frac{1}{2}-t)\leq \frac{28}{14}$

$\frac{1}{2}-t\leq 2$

$-t\leq 2-\frac{1}{2}$

$-t\leq \frac{3}{2}$

t ≥ - $\frac{3}{2}$

2). 15k + 11 ≤ 18k - 5

15k - 18k ≤ -5 - 11

-3k ≤ - 16

3k ≥ 16

k ≥ $\frac{16}{3}$

3). 44y > 11 + 88y - 22y

44y > 11 + 66y

44y - 66y > 11

-22y > 11

22y < -11

$\frac{22y}{22}$

y < $-\frac{1}{2}$

4). $\frac{7}{9}(b - 27) > \frac{49}{81}$

$\frac{7}{9}(b - 27)\times \frac{9}{7} > \frac{49}{81}\times \frac{9}{7}$

(b - 27) > $\frac{7}{9}$

b > $\frac{7}{9}+27$

b > $\frac{250}{9}$

5). 11w - 8w ≥ 14w

3w - 14w ≥ 0

-11w ≥ 0

w ≤ 0

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3 years ago

If x/5+6=-14 then x equals

yanalaym [24]

Answer:

x = - 100

Step-by-step explanation:

Given

$\frac{x}{5}$ + 6 = - 14 ( subtract 6 from both sides )

$\frac{x}{5}$ = - 20

Multiply both sides by 5 to clear the fraction

x = 5 × - 20 = - 100

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3 years ago

After running for 3 1/2 km, Sacha only completed half the total distance of a marathon . What is the complete distance of that m

Gre4nikov [31]

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Answer: 7 km

Explanation:

3.5 x 2 = 7

I hope this helped!

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- Zack Slocum

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3 years ago

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